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- Thread starter LagrangeEuler
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mfb

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It is an experimental result that you can find the particles in those "forbidden" regions with some probability.How we know that in case of finite potential well that particle is in the region where ##V>E##.

You can use quantum mechanics to calculate that probability.

Do you want a good position or a good energy measurement? Those will lead to different results.How we know what is energy of the particle in moment when we localize it in the region with potential ##V##.

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It is an experimental result that you can find the particles in those "forbidden" regions with some probability.

You can use quantum mechanics to calculate that probability.

Do you want a good position or a good energy measurement? Those will lead to different results.

That is not my question. I asked how we know energy of the particles in different region?

http://en.wikipedia.org/wiki/Finite_potential_well

"There are two possible families of solutions, depending on whether E is less than (the particle is bound in the potential) or E is greater than (the particle is free)."

How we know from measurement is it particle free or not?

I want to know more about this measurements. I know how to solve this problem with use og mathematics.

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mfb

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That does not exist. The particle has a unique [expectation value of the] energy, which does not depend on the position.That is not my question. I asked how we know energy of the particles in different region?

Measure the energy of the particle ;). Or just see if it stays in the well (and in its direct vicinity) - if it does, it is not free, otherwise it is free.http://en.wikipedia.org/wiki/Finite_potential_well

"There are two possible families of solutions, depending on whether E is less than (the particle is bound in the potential) or E is greater than (the particle is free)."

How we know from measurement is it particle free or not?

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What about bond states in the well. If finite potential well is symmetric then for ##E<V##, there are bond states. If isn't symmetric then could be bound states. Why is that physically?

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mfb

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What about bound states? Well, those are the states with E<V, what exactly are you asking?

And which symmetry do you mean?

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mfb

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In more than 1 dimension, some potential wells are so shallow that they do not have bound states. In 1 dimension, you always have a bound state.Why I don't have it always.

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No you don't have always bond state! That is the problem!

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mfb

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