Kronecker Delta: A Relativity and Tensor Explanation

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The Kronecker delta is a function defined for two integers, yielding a value of 1 when the integers are equal and 0 otherwise, often represented as \deltaij. This function is crucial in tensor analysis, particularly in relativity, as it simplifies expressions involving summation over indices. For example, in the context of event coordinates, the expression x^\mu \delta_{\mu \nu} reduces to x^\nu due to the properties of the Kronecker delta. Its significance lies in its ability to act as a metric tensor in Euclidean space, facilitating calculations in tensor equations. Understanding the Kronecker delta is essential for grasping more complex concepts in relativity and tensor calculus.
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I keep seeing this come up in relativity and tensor resources but I have no idea wht the heck it means. Could someone explain it to me?
 
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Terilien said:
I keep seeing this come up in relativity and tensor resources but I have no idea wht the heck it means. Could someone explain it to me?

The Kronecker delta is a function of two integers. If the integers are the same then the value of the function is 1. Otherwise it is zero. This function can be represented as a matrix. The notation for this function is \deltaij.

Pete
 
pmb_phy said:
The Kronecker delta is a function of two integers. If the integers are the same then the value of the function is 1. Otherwise it is zero. This function can be represented as a matrix. The notation for this function is \deltaij.

Pete


Why is it important in tensor analysis?
 
Example from relativity. Let the coordinates of an event be \left\{x^0 , x^1 , x^2 , x^3 \right\}. Then, using the summation convention of summing over repeated indices,

x^\mu \delta_{\mu \nu} = x^0 \delta_{0 \nu} + x^1 \delta_{1 \nu} + x^2 \delta_{2 \nu} + x^3 \delta_{3 \nu}.

Since the Kronecker delta is zero unless both indices are equal, only one of the terms in the above sum survives. We don't know which one, but we know it's the one that has \nu as its first index. Therefore, the sum equals x^\nu .
 
Last edited:
Terilien said:
Why is it important in tensor analysis?
because it's a metric tensor of euclidean space? dunno. the "importance" asigned to things by different people is quite biased.
 

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