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Label Conversion factor (Temperature)

  1. May 22, 2012 #1
    1. The problem statement, all variables and given/known data
    On a hypothetical temperature scales X and Y, the ice and steam points of water are 30 and 150, and -15 and 200° respectively
    a. 32 X° is equivalent to how many Y°
    b. 100 °X is equivalent to how many K?

    2. Relevant equations
    Given value - (ice point)/ steam point = Unknown - (ice point)/ steam point - (ice point)


    3. The attempt at a solution
    32-(30)/150-(30) = Y-(-15)/200-(-15)
    My answer is incorrect!
     
  2. jcsd
  3. May 22, 2012 #2

    gneill

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    Staff: Mentor

    Hi kewlergel, Welcome to Physics Forums.

    I don't follow logic of your Relevant Equation; it could just be my thick-headedness :smile:

    However, since temperature scales are linear you would expect there to be a linear relationship between the two scales: one of the form y = mx + b. You have data points for particular equivalent values from each scale, so why not set up the equations to solve for m and b?
     
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