Minimum Angle for 100-N Ladder Against Wall

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SUMMARY

The discussion focuses on calculating the minimum angle at which a 100-N uniform ladder, 8.0m long, can rest against a smooth vertical wall without slipping. Key principles include the equilibrium of forces and torques, specifically that the sum of all forces and the sum of torques must equal zero. The coefficient of static friction between the ladder and the floor is 0.40, which plays a crucial role in determining the angle. The solution involves applying trigonometric functions to relate the forces acting on the ladder.

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Homework Statement


A 100-N uniform ladder, 8.0m long, rests against a smooth vertical. The coefficient of static friction between ladder and floor is 0.40. What minimum angle can the ladder make with the floor before it slips?

The Attempt at a Solution



Not really sure where to start here. I do know since they told us the ladder is uniform, that i can somehow use the middle of the ladder as something. The sum of torques must be zero if the ladder isn't moving as well. But not quite sure what to do. Any help would be appreciated.
 
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the sum of all forces is also zero if the ladder isn't moving (friction + normal force+gravitional force(=weight))
so you have two basic conditions:
1)sum of all forces is zero
2)as you said , the sum of torques is also zero

you will calculate the torque(? moment of force) in the point where it touches the wall, and in the point where it touches the floor, and each of those equal zero ( here you will use the middle of ladder) actually it is probably necessary to calculate it around one of this points...

and at the end some elementary trigonometrics...

i am sorry, if I used some of the terms incorrectly, english is not my mother tongue, so...
and I apologize for any physics mistake in the above text, I am just a benevolent student
 

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