Lang's Algebra Ch 1 Problem 12(c): Ambiguous Group Law

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SUMMARY

The discussion centers on Problem 12(c) from Chapter 1 of Lang's Algebra (revised third edition), which involves defining a group G = N x H with a specific multiplication law. The ambiguity arises from the notation f(b) in the expression (a,b)(a',b') = (a'f(b)a',bb'), where f: H --> Aut(N) is a homomorphism. Participants conclude that f(b) should be applied to a', aligning with the construction of the semidirect product of two groups. Clarification on notation is essential for accurate interpretation of the problem.

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  • Understanding of group theory concepts, specifically semidirect products.
  • Familiarity with homomorphisms and automorphisms in group theory.
  • Knowledge of notation and operations in algebraic structures.
  • Experience with Lang's Algebra, particularly the revised third edition.
NEXT STEPS
  • Study the construction and properties of semidirect products in group theory.
  • Review the definitions and examples of homomorphisms and automorphisms.
  • Examine additional problems in Lang's Algebra to reinforce understanding of group operations.
  • Explore alternative texts on group theory for different perspectives on similar problems.
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Students of abstract algebra, particularly those working through Lang's Algebra, and educators seeking to clarify group theory concepts related to semidirect products and homomorphisms.

eastside00_99
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I am working the problems in Lang's Algebra. I am on number 12(c) on Chapter 1 [revised third edition], it states

let H and N be groups and let f: H --> Aut(N) be given homomorphism Define G = NxH with the law

(a,b)(a',b') = (a'f(b)a',bb').

the problem is that f(b) is a member of Aut(N) and so the definition is ambiguous at best. I mean I suppose it could mean f(b) applied to a' (or even applied a). But this doesn't fit the notation of the rest of the book. Any comments on this?
 
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(Should that be "(a f(b) a', bb')" instead?)

I'm pretty sure it's supposed to mean f(b) applied to a'. It looks like the exercise is attempting to walk you through the construction of the semidirect product of two groups.
 
morphism said:
(Should that be "(a f(b) a', bb')" instead?)

I'm pretty sure it's supposed to mean f(b) applied to a'. It looks like the exercise is attempting to walk you through the construction of the semidirect product of two groups.

yeah i meant a instead of a' up there. Ok, I guess that has to be what it is then. Thanks.
 

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