How to Find the Laplace Transform of an Unknown Solution Function?

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SUMMARY

The discussion focuses on finding the Laplace Transform of the unknown solution function for the initial value problem defined by the differential equation y'' + 4y' - 5y = te^t, with initial conditions y(0)=1 and y'(0)=0. The key takeaway is that Laplace transforms are linear, allowing for the individual transformation of each term in the equation. The formula for the Laplace transform of a derivative is provided, specifically L{y^{(n)}} = s^nY(s) - s^{n-1}y^{(n-1)}(0) - s^{n-2}y^{(n-2)}(0) - ... - y(0), which is crucial for solving the problem.

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Lucy77
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This one has me stumped


Find the Laplace Transform of the unknown solution function for the following initial value problem:

y'' + 4y' - 5y = te^t, y(0)=1, y'(0)= 0

(Do Not actually find the function, only its transform. Then, without carrying out the steps, indiacate briefly how you would proceed to find the unknown solution function.)

Thanks
 
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As with your other question, Laplace transforms are linear thus you can do each elemnt individually. What have you done thus far?
 
Also, L \{ y^{(n)} \}

where n is the derivative is

s^nY(s)-s^{n-1}y^{(n-1)}(0)-s^{n-2}y^{(n-2)}(0)-...-y(0)

PS. click on the equation to see how to use LaTex extensions. A little popup box should appear with a "click to read LaTex guide" at the bottom.

Good luck.
 

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