Laplace transform (translation on the s-axis)

Click For Summary
SUMMARY

The discussion centers on solving the inverse Laplace transform L-1{[(2s-1)]/[(s2)(s+1)3]} using the translation property on the s-axis. Participants suggest that while the problem's complexity arises from the different exponents in the denominator, it may still be possible to utilize partial fractions in conjunction with the translation property. The equation L{f(t)eat} = F(s-a) is referenced as a key tool for applying the translation property effectively. Ultimately, the consensus indicates that partial fractions can be used alongside translation, depending on the specific homework requirements.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with the translation property of Laplace transforms
  • Knowledge of partial fraction decomposition
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the convolution theorem for Laplace transforms
  • Learn how to apply the translation property in Laplace transforms
  • Practice solving inverse Laplace transforms using partial fractions
  • Explore advanced techniques in Laplace transform applications
USEFUL FOR

Students studying differential equations, mathematicians focusing on transform methods, and anyone looking to deepen their understanding of Laplace transforms and their applications in engineering and physics.

PhysicsCollegeGirl
Messages
6
Reaction score
2

Homework Statement


L-1{[(2s-1)]/[(s^2)(s+1)^3]}

Homework Equations


L{f(t)e^(at)}=F(s-a)

The Attempt at a Solution


I have tried million ways but the different exponents in the denominator are throwing me off.
The other problem is that I cannot use partial fractions, the homework instructions require me to use translation in the s-axis.
But now I am thinking that I have to use partial fractions anyway? Can someone just tell me if there is a way to solve it without using partial fractions, and I will keep at it. If there is not, I can move on with my life in peace. Thank you!
 
Physics news on Phys.org
PhysicsCollegeGirl said:

Homework Statement


L-1{[(2s-1)]/[(s^2)(s+1)^3]}

Homework Equations


L{f(t)e^(at)}=F(s-a)

The Attempt at a Solution


I have tried million ways but the different exponents in the denominator are throwing me off.
The other problem is that I cannot use partial fractions, the homework instructions require me to use translation in the s-axis.
But now I am thinking that I have to use partial fractions anyway? Can someone just tell me if there is a way to solve it without using partial fractions, and I will keep at it. If there is not, I can move on with my life in peace. Thank you!
I haven't worked it myself, but judging from what the problem looks like, I would write it as$$
\frac{2s-1}{s^2}\cdot \frac 1 {(s+1)^3}$$and use the convolution of the inverses of the two fractions. The second one would give you a chance to use your translation formula.
 
PhysicsCollegeGirl said:

Homework Statement


L-1{[(2s-1)]/[(s^2)(s+1)^3]}

Homework Equations


L{f(t)e^(at)}=F(s-a)

The Attempt at a Solution


I have tried million ways but the different exponents in the denominator are throwing me off.
The other problem is that I cannot use partial fractions, the homework instructions require me to use translation in the s-axis.
But now I am thinking that I have to use partial fractions anyway? Can someone just tell me if there is a way to solve it without using partial fractions, and I will keep at it. If there is not, I can move on with my life in peace. Thank you!

I doubt that you have tried more than 10,000 ways. Anyway, if I were doing it I would first expand it into partial fractions, then use the "translation" property on 3 of the 5 terms.

Whether that is OK depends on whether your instructions imply that you must use only the translation property and nothing else, or whether it just requires you to use translation somewhere in the solution. That is something only you can decide.
 
Last edited:

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K