Laplace transformation t^(3/2)

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SUMMARY

The Laplace transform of the function f(t) = 10t^(3/2) - e^(-7t) is calculated using the formula L{t^k} = Γ(k)/s^(k+1), where Γ represents the gamma function. The correct transformation for the term 10t^(3/2) results in (10Γ(5/2))/(s^(5/2)), leading to the final expression of (10π(3/2))/(2s^(5/2)) - (1/(s+7)). It is crucial to recognize that t^(1/2) and t^(3/2) yield different Laplace transforms due to their distinct powers.

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Homework Statement


Just a quick question concerning a Laplace transformation...
Find the Laplace transform of the following function:
f(t)=10t3/2-e(-7t)


Homework Equations





The Attempt at a Solution


I wasn't sure what to do with the t3/2 so I just followed the formula for t1/2 and I got this:

(10pi(3/2))/(2s5/2)-(1/(s+7))

Is there anything wrong with this?
 
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t1/2 and t3/2 are different functions, so it should be expected that their Laplace transforms would be different.
L{tk - 1} = \Gamma(k)/sk, where \Gamma represents the gamma function.

\Gamma(z)~=~\int_0^{\infty} t^{z - 1}~e^{-t}dt
Hope that helps.
 

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