- #1

JJfortherear

- 14

- 0

## Homework Statement

Rectangular pipe, infinite in the z direction. The sides in the y-z plane (at x=0 and x=a) are held at V=0, while the sides in the x-z plane (at y=0 and y=b) are held at V=V

_{0}

Explain why there cannot be a non-trivial solution to this configuration.

## Homework Equations

General form of solution is (A*e

^{ky}+ B*e

^{-ky})*(C*sin(kx)+D*cos(kx))

D is zero from b.c. (V=0 at x=0)

## The Attempt at a Solution

So Griffiths has this problem (and a non-trivial solution), except the pipe is symmetric about the x axis, so V(y)=V(-y), and from that, A=B. My version lacks this symmetry (and thus lacks enough conditions to solve for the constants), but I can't imagine the solutions fly out the window just from a shift of coordinates. Any help?