Laplace's Equation in Cylindrical Coordinates

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Homework Help Overview

The problem involves finding the electric potential in a long copper pipe, which is cut in half and held at different voltages. The context is Laplace's equation in cylindrical coordinates, specifically addressing the potential distribution in a two-dimensional scenario.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply separation of variables to solve Laplace's equation but expresses confusion regarding the boundary conditions and their application. Some participants suggest breaking the problem into regions and using Fourier analysis to address the periodic nature of the potential.

Discussion Status

Participants are exploring different interpretations of the boundary conditions and the implications for the potential function. There is acknowledgment of the need for Fourier analysis to determine constants, and some clarity has been achieved regarding the periodicity of the potential.

Contextual Notes

The discussion includes uncertainty about the correct boundary conditions and the representation of the potential as a sine or cosine function. The original poster questions the assumption that the potential should approach zero at infinity, indicating a need for further clarification on the problem setup.

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Homework Statement


A long copper pipe, with it's axis on the z axis, is cut in half and the two halves are insulated. One half is held at 0V, the other at 9V. Find the potential everywhere in space.

Homework Equations



[tex]\nabla^2V=0[/tex]

The Attempt at a Solution



Alright. This is a laplace's equation problem in two dimensions, since the potential should be independent of z because the pipe is infinite. Using separation of variables( [tex]V=R\Phi[/tex]) the solution to the two dimensional Laplace's EQ in cylindrical coordinates is:

[tex]R(r)=ar^k+br^-k[/tex]

[tex]\Phi(\phi)=A\sin(k\phi) + B\cos(k\phi)[/tex]

w/ [tex]V=R(r)\Phi(\phi)[/tex]I am getting confused when I try to apply boundary conditions to this problem. Here is what I think the boundary conditions should be:

1) V should go to zero as r goes to infinity. (I don't think this is right, since the pipe is infinite, but I am not sure.)

2)V=0 for phi between 0 and pi, r=radius of pipe

3)V=9 for phi between 0 and 2pi, r=radius of pipe.

I can't figure out how to actually use these to eliminate any of the constants. Any help and hints would be greatly appreciated.
 
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First of all you have to break the problem into two regions [itex]V_{in}[/itex] inside the pipe and [itex]V_{out}[/itex] outside the pipe. In order for [itex]V[/itex] to be finite to each region you can eleminate [itex]\alpha[/itex] or [itex]\beta[/itex] in eah region.
The potential [itex]V[/itex] must be periodical for [itex]\phi[/itex] thus you know [itex]k[/itex].
Lastly you have to use the superposition principle and Fourier analysis for the remaining constants.
 
OK. It seems the part screwing me up is finding k. The potential is periodic in Phi, but it seems more like a step function. I guess I'm saying that I don't understand how can represent that potential as a sine or cosine term, no matter what k happens to be.

Could you elaborate on that part of the problem?
 
Since the potential must be periodic in [itex]\phi[/itex] you must have [itex]k\in \mathbb{N}[/itex]. Thus the solution is

[tex]V_{in}(r,\phi)=\frac{A_0}{2}+\sum_{n=1}^\infty r^n\left(A_n\,\cos(n\,\phi)+B_n\,\sin(n\,\phi)\right)[/tex]

The boundrary conditions read

[tex]u(R,\phi)=\left\{\begin{matrix} 0 & 0<\phi<\pi\cr 9 & \pi<\phi<2\,\pi \end{matrix}[/tex]

The constants [itex]A_n,\,B_n[/itex] can be found by Fourier analysis. Can you do that?
 
Yes, I am fine with Fourier analysis. The boundary condition were just confusing the heck out of me. I don't quite no why either. I guess I just did not recognize that I had to use Fourier anaylsis. Thank you! I think I got it now.
 
Last edited:

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