LaTeX help....larger bracketing symbols

[Petrus]

Hello MHB,
I am curious how I can make these "[" "]" bigger in latex cause it does not look nice when I do it. Exemple:
$$[3xy+\frac{3x}{3y}\ln(2)]_{\frac{x^2}{3}}^x$$
Notice just I did just type some number but how can I make it a lot nicer in latex cause that does not really look good.

Regards,

 

[Opalg]

Re: Latex help

Hello MHB,
I am curious how I can make these "[" "]" bigger in latex cause it does not look nice when I do it. Exemple:
$$[3xy+\frac{3x}{3y}\ln(2)]_{\frac{x^2}{3}}^x$$
Notice just I did just type some number but how can I make it a lot nicer in latex cause that does not really look good.

Regards,

\left[ and \right] will set the size automatically: $$\left[3xy+\frac{3x}{3y}\ln(2)\right]_{\frac{x^2}{3}}^x$$.

Alternatively, you can set the size manually, using commands like \Bigl[ and \Bigr], which will give $$\Bigl[3xy+\frac{3x}{3y}\ln(2)\Bigr]_{\frac{x^2}{3}}^x$$. The available sizes, in increasing order, are \bigl and \bigr, \Bigl and \Bigr, \biggl and \biggr, \Biggl and \Biggr.

 

[alyafey22]

Re: Latex help

One question , can we just scale up one bracket ?

EDIT , sorry I didn't realize that Opalg already posted that .

 

[Petrus]

Re: Latex help

Thanks evryone for the answer! I will try memorize this method :)Regards,

 

[Evgeny.Makarov]

Re: Latex help

\left[ and \right] will set the size automatically: $$\left[3xy+\frac{3x}{3y}\ln(2)\right]_{\frac{x^2}{3}}^x$$.

To add to this, there is also \middle:
\[
P\left(A=2\middle|\frac{A^2}{B}>4\right)
\]

and "If a delimiter on only one side of an expression is required, then an invisible delimiter on the other side may be denoted using a period (.)":
\[
\left.\frac{x^3}{3}\right|_0^1
\]
(Wikibooks).

 

[MarkFL]

Re: Latex help

...
and "If a delimiter on only one side of an expression is required, then an invisible delimiter on the other side may be denoted using a period (.)":
\[
\left.\frac{x^3}{3}\right|_0^1
\]...

Thank you tremendously...I had encountered this problem for example with:

$$\frac{dy}{dx}|_{x=1}$$

where using only the \left command would not render. Now I may write:

$$\left.\frac{dy}{dx} \right|_{x=1}$$

Very helpful tip...most appreciated! (Yes)