Learning physics on my own need a little help

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Homework Help Overview

The discussion revolves around determining the direction of a person walking a specific distance north and east, specifically 3.0 km north and 4.0 km east. The subject area pertains to basic trigonometry and vector analysis in physics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using trigonometric functions, specifically the tangent function, to find the angle of direction. There are questions regarding the exact wording of the problem as presented in the textbook.

Discussion Status

Some participants have provided guidance on using the tangent function to calculate the angle, while others confirm the wording of the problem. There is an ongoing exploration of the calculations involved, but no consensus has been reached regarding the correctness of the angle derived.

Contextual Notes

One participant notes that the question was worded exactly as it appears in the textbook, which may imply constraints on how the problem can be approached or interpreted.

oG riT
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what is the direction of a person that walks 3.0-km North and 4.0-km East?
and can you tell me how you got the answer please
 
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oG riT said:
what is the direction of a person that walks 3.0-km North and 4.0-km East?
and can you tell me how you got the answer please
Hello oG riT. Welcome to PF !

To answer your question, you need to use trigonometry.

Is that question worded exactly as it was given to you in the textbook?
 
Use Tan function to find the angle. (θ represents an angle)
Tanθ = opp/adj
= 4km / 3km
θ = tan-1(4km/3km)

So the direction would be [N θ E]
 
yes that's how it was worded
 
Ace. said:
Use Tan function to find the angle.


(θ represents an angle)
Tanθ = opp/adj
= 4km / 3km
θ = tan-1(4km/3km)

So the direction would be [N θ E]

i got 36.9 is that right?
 

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