Left & Right Limits Of A Function (Finding Values Of A Variable)

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Homework Help Overview

The discussion revolves around finding the left and right limits of a function involving a variable "m." Participants are attempting to understand how to evaluate these limits without specific x or y coordinates provided in the problem statement.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express confusion about the requirements of the problem and the meaning of the limits. There are attempts to clarify how to evaluate the limit expression given the lack of specific coordinates. Some participants suggest isolating "m" in terms of other variables as a potential approach.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing guidance on evaluating the limit expression. However, there is no explicit consensus on the approach to take, and multiple interpretations of the problem are being discussed.

Contextual Notes

Participants note the absence of specific values for x or y, which complicates the evaluation of the limits. The original poster's understanding of the question is questioned, indicating a potential misunderstanding of the problem setup.

CallMeShady
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Homework Statement


11rddt5.jpg



Homework Equations


Only ones I know that are relevant are the equations shown in the question (for the left and right limits).


The Attempt at a Solution


The difficulty that I am having right not is comprehending what is really being asked from the question. From what I understand, then question is asking the "m" values from the left and right limits at the top, and the value for "m" when those limits are the same. However, how would I go about finding the value of "m" if I have no x or y co-ordinates given?
 
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CallMeShady said:

Homework Statement


11rddt5.jpg



Homework Equations


Only ones I know that are relevant are the equations shown in the question (for the left and right limits).


The Attempt at a Solution


The difficulty that I am having right not is comprehending what is really being asked from the question. From what I understand, then question is asking the "m" values from the left and right limits at the top, and the value for "m" when those limits are the same. However, how would I go about finding the value of "m" if I have no x or y co-ordinates given?
What is \displaystyle \lim_{x\to\,1}(8x^3-2m)\ ?
 
SammyS said:
What is \displaystyle \lim_{x\to\,1}(8x^3-2m)\ ?

That is not given (everything above that I posted is the only thing given). Or are you suggesting that I should calculate that to solve this problem. That expression just defines the limit from the left side. I am unsure on how to calculate that.
 
CallMeShady said:
That is not given (everything above that I posted is the only thing given). Or are you suggesting that I should calculate that to solve this problem. That expression just defines the limit from the left side. I am unsure on how to calculate that.
What do you mean, it's not given?

I'm asking you to evaluate the limit, \displaystyle \lim_{x\to\,1}(8x^3-2m)\,, if you can. If you can't, I don't how you can do this problem at all.
 
SammyS said:
What do you mean, it's not given?

I'm asking you to evaluate the limit, \displaystyle \lim_{x\to\,1}(8x^3-2m)\,, if you can. If you can't, I don't how you can do this problem at all.


I don't see how I can evaluate that limit... I could isolate "m" though by temporarily assigning "f(x)" as "y". Then I could isolate "m" in terms of "y" => "m(y)".
 
Sammy is not asking you to solve for m (i.e., isolate me) - just evaluate the limit, which by the way should be
$$\lim_{x \to -1^{-}}(8x^3 - 2m) $$

Your answer should be in terms of m.
 
CallMeShady said:
I don't see how I can evaluate that limit... I could isolate "m" though by temporarily assigning "f(x)" as "y". Then I could isolate "m" in terms of "y" => "m(y)".
\displaystyle \lim_{x\to\,1}(8x^3-2m) = 8(1)^3-2m=8-2m

That's all there is to it !
 
I can't believe how easy this question actually was... I was making it too complex due to the fact that I wasn't comprehending this question very well. A sincere thank you to Mark and Sammy for their assistance. I really appreciate it.
 
Last edited:
CallMeShady said:
I can't believe how easy this question actually was... I was making it too complex due to the fact that I wasn't comprehending this question very well. A sincere thank you to Mark and Sammy for their assistance. I really appreciate it.

So, what are you results?
 

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