# Legendre polynomial integration

## Homework Statement

int x^m*P_n(x) dx=0 where integration is from (-1) to (+1).Given m<n

## The Attempt at a Solution

I took integrand F(x) and saw that F(-x)=(-1)^(m+n)*F(x)
should that help anyway?

## Homework Statement

int x^m*P_n(x) dx=0 where integration is from (-1) to (+1).Given m<n

## The Attempt at a Solution

I took integrand F(x) and saw that F(-x)=(-1)^(m+n)*F(x)
should that help anyway?

um....the integration is from -1 to 1, so first thing come to my mind is to make good use of the orthogonality property of Legendre polynomials.
then...may be you can try Mathematical Induction for both odd and even polynomails with leading terms x^m , m< n

you may have a look on
http://en.wikipedia.org/wiki/Legendre_polynomial

it may not be a fast and smart method..
but i think it may works

can anyone think of any better way?? Regarding the orthogonality,it appears that x^m needs to be equal to some P_m(x).It would be too much particular case.Isn't it?

Boas suggests to go for integration by parts.But it is so much horrible that I am stuck after 1st step.Can anyone please help?

OK,you were correct.Because,
the Legendre polynomials are complete on [-1,1], so:

x^m=a linear combination of P_0,P_1,P_2,...P_m
where m<n

Hence the result follow directly from orthogonality.

OK,you were correct.Because,
the Legendre polynomials are complete on [-1,1], so:

x^m=a linear combination of P_0,P_1,P_2,...P_m
where m<n

Hence the result follow directly from orthogonality.

Yes.
you got the point.
just rewrite x^m in terms of Pn(x) and you may neglect those constants
in this case.

No need to neglect the constants.They simply go outside the integrals.

There is a question where you should find a formula for P-n(0) using the Legendre polynomials:
P-n(x)=1/(2^n*n!) d^n/dx^n(x^2-1)^n , n=0,1,2,3......

I tried to derive seven times by only substituting the n untill n=7,I did that because i wanted to find something that i can build my formula but i could not.
anyone can help?