Legendre polynomial integration

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Homework Help Overview

The discussion revolves around the integration of the product of a power of x and Legendre polynomials over the interval from -1 to 1, specifically addressing the case where the power m is less than the degree n of the polynomial. Participants explore the implications of orthogonality properties of Legendre polynomials in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the orthogonality property of Legendre polynomials and consider mathematical induction as a potential method. There are questions about the implications of expressing x^m in terms of Legendre polynomials and the challenges of integration by parts.

Discussion Status

The discussion is active, with participants offering various approaches and questioning the assumptions underlying the problem. Some suggest leveraging orthogonality directly, while others express difficulties with integration techniques. No consensus has been reached, but several productive lines of inquiry are being explored.

Contextual Notes

Participants note the specific condition that m must be less than n, and there is mention of the completeness of Legendre polynomials on the interval [-1, 1]. The integration limits and the nature of the polynomials are central to the discussion.

neelakash
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Homework Statement



int x^m*P_n(x) dx=0 where integration is from (-1) to (+1).Given m<n

Homework Equations





The Attempt at a Solution



I took integrand F(x) and saw that F(-x)=(-1)^(m+n)*F(x)
should that help anyway?
 
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neelakash said:

Homework Statement



int x^m*P_n(x) dx=0 where integration is from (-1) to (+1).Given m<n

Homework Equations


The Attempt at a Solution



I took integrand F(x) and saw that F(-x)=(-1)^(m+n)*F(x)
should that help anyway?

um...the integration is from -1 to 1, so first thing come to my mind is to make good use of the orthogonality property of Legendre polynomials.
then...may be you can try Mathematical Induction for both odd and even polynomails with leading terms x^m , m< n

you may have a look on
http://en.wikipedia.org/wiki/Legendre_polynomial

it may not be a fast and smart method..
but i think it may works

can anyone think of any better way??:smile:
 
Regarding the orthogonality,it appears that x^m needs to be equal to some P_m(x).It would be too much particular case.Isn't it?

Boas suggests to go for integration by parts.But it is so much horrible that I am stuck after 1st step.Can anyone please help?
 
OK,you were correct.Because,
the Legendre polynomials are complete on [-1,1], so:

x^m=a linear combination of P_0,P_1,P_2,...P_m
where m<n

Hence the result follow directly from orthogonality.
 
neelakash said:
OK,you were correct.Because,
the Legendre polynomials are complete on [-1,1], so:

x^m=a linear combination of P_0,P_1,P_2,...P_m
where m<n

Hence the result follow directly from orthogonality.

Yes.
you got the point.
just rewrite x^m in terms of Pn(x) and you may neglect those constants
in this case.
 
No need to neglect the constants.They simply go outside the integrals.
 
There is a question where you should find a formula for P-n(0) using the Legendre polynomials:
P-n(x)=1/(2^n*n!) d^n/dx^n(x^2-1)^n , n=0,1,2,3...

I tried to derive seven times by only substituting the n until n=7,I did that because i wanted to find something that i can build my formula but i could not.
anyone can help?
 

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