Legendre Transformation of Lagrangian density ?

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DOTDO
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Hi

I began to study the basics of QED.

Now I am studying Lagrangian and Hamiltonian densities of Dirac Equation.

I'll call them L density and H density for convenience :)Anyway, the derivation of the H density from L density using Legendre transformation confuses me :(

I thought because parameters of them are space-time components, it should be


bandicam 2015-05-03 11-13-28-477.jpg

But I found that this is related to the De Doner - Weyl Theory,

and the H density used in textbook is
bandicam 2015-05-03 11-13-34-326.jpg

where the dot represents time derivative.So, my question is,

why we consider Legendre transformation on only time derivative of phi ?

Is it just 'defined' to consider energy of the system?

Then what does the covariant H density defined in the De Donder - Weyl theory mean?
 
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From the lagrangian density [itex]\mathcal{L}[/itex], you can define the canonical stress-energy tensor [itex]\mathcal{T}[/itex] as follows:

[itex]\mathcal{T}^{\mu \nu} = \dfrac{\partial \mathcal{L}}{\partial \partial_\mu \phi_j} \partial^\nu \phi_j - g^{\mu \nu} \mathcal{L}[/itex]

This is a conserved current in the first index:

[itex]\partial_\mu \mathcal{T}^{\mu \nu} = 0[/itex]

Then you can define a hamiltonian density [itex]\mathcal{H}[/itex] in terms of [itex]\mathcal{T}[/itex]:

[itex]\mathcal{H} = \mathcal{T}^{tt} =\dfrac{\partial \mathcal{L}}{\partial \partial_t \phi_j} \partial^t \phi_j - g^{tt} \mathcal{L}[/itex]

This is the same as the expression in the textbook, if you're using the metric where [itex]g^{tt} = +1[/itex] and defining [itex]\dot{\phi_j} = \partial_t \phi_j[/itex]

The hamiltonian is the integral of the hamiltonian density over all space:

[itex]H = \int d^3 x \mathcal{H}[/itex]

It's the hamiltonian, not the hamiltonian density, that is constant:

[itex]\dfrac{d}{dt} H = 0[/itex]