Lenear algebra independance theoretical question

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The discussion centers on the concept of linear independence in the vector space V=Q^4 over Q, specifically examining whether the set of vectors (v1, v2, v3, v4) can serve as a basis for V. A basis requires that the vectors span the space, are linearly independent, and match the dimension of the space. Since V has a dimension of 4 and the set (v1, v2, v3, v4) contains only 4 vectors, it cannot be a basis if v5 is a linear combination of the others, as this would violate the linear independence requirement.

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there is a space V=Q^4 over Q .
there is a series of vectors (v1 ,v2 ,v3,v4,v5)
that spans V
does the series
(v1 ,v2 ,v3,v4) is a basis of V?
if it is explain
if not give a counter example??

we could have that v5 is a linear combination of others.

??
 
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transgalactic said:
there is a space V=Q^4 over Q .
there is a series of vectors (v1 ,v2 ,v3,v4,v5)
that spans V
does the series
(v1 ,v2 ,v3,v4) is a basis of V?
if it is explain
if not give a counter example??

we could have that v5 is a linear combination of others.

??
A basis for a vector space has three properties.
1) It spans the space.
2) The vectors in it are linearly independent.
3) The number of vectors in it is the same as the dimension of the vector space.

Further, if any two of those are true, the third must be. You are told that {v1, v2, v3, v4} spans V and you can certainly see that there are four vectors in that set. What is the dimension of V?
 

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