Is the Upper Optical Path Longer than the Lower One in Diagram 2?

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SUMMARY

The discussion confirms that in Diagram 2, the optical path of the upper ray (S1P - t + ut) is indeed longer than that of the lower ray (S2P) when the refractive index (u) is greater than 1. This conclusion is based on the relationship S1P - t + ut > S2P, where S2P equals S1P in the context of the upper diagram. The negative result obtained when calculating S2P minus the upper ray's path indicates a fundamental misunderstanding of the optical path lengths.

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desmond iking
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Homework Statement



for diagram 2 , i just can't understand why S1P -t + ut (upper ray ) is longer than the lower light ray (S2P) , ? if I take S2P minus ( S1P -t + ut ) , then i would get mt t (thickness ) is negative , which is indeed wrong! so it has shown that optical path of the upper ray is longer than the optical path of lower ray ...

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S1P - t + ut > S2P if u>1, as S2P=S1P based on the upper diagram. I guess u is your refractive index? Regular materials have a refractive index larger than 1, so the upper path is longer.
 
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