Length vs. Period: Comparing Linear & Quadratic Relationships

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Homework Help Overview

The discussion centers around the relationship between the length of a pendulum and its period, with participants exploring the implications of their experimental data and the relevant equations. The original poster presents data from a pendulum lab, noting a potential linear relationship between length and period, while also considering the squared period versus length relationship.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss plotting period squared against length and the implications of different equations for the period of a pendulum. Questions arise about which equations to use and how to interpret the graphs.

Discussion Status

Some participants have provided guidance on how to approach the graphing of the data, suggesting plotting T^2 versus l to find the acceleration due to gravity. However, there is no clear consensus on the best approach, and some participants express confusion about the topic.

Contextual Notes

One participant mentions being in grade 11 and struggling with a related assignment involving designing a car powered by a suspended mass, indicating a potential overlap in physics concepts being discussed.

petern
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I did a pendulum lab and determined that length affected the period. So the values got where:

10 cm = 6.47 s
15 cm = 7.895 s
20 cm = 8.94 s
25 cm = 9.89 s
30 cm = 10.5 s
35 cm = 11.905 s

With these values, it seems like graphing this straight as it is results in a linear line, but I searched around and found that others did period^2 vs. length.

What should I do?
 
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well the equation for the period of a pendulum is given by
[tex]T=2\pi\sqrt{\frac{l}{g}}[/tex]

so can plot T^2 vs. l or plot T vs.sqrt{l} and you'll get it
 
Which equation should I use to describe the T^2 graph. My friend said it includes length, acceleration, and radius.
 
Well both are the same...if you plot T^2 vs. l the gradient of that graph would be [itex]\frac{4\pi^2}{g}[/tex] and you can find g from there[/itex]
 
Hey please help me out here ...i m in grade 11 and i got this assignmnt ..where i have to design a car that will move forward from a suspended mass...i have no idea wot to do ... itz due this frdaypleasez i really need help...none of my grou members are helping me out ..
 
He said it was l=a/r since the T^2 graph is linear and the slope of that graph is the acceleration, is he right?
 
Don't hijack this thread...make your own
 
The experiment would usually follow for the equation i typed
 
wot do u mean...i m new.i dunoo how to make a mnew thread!
 
  • #11
ohh thanx..i did ...do u think sumone will help me out??
 
  • #12
If you show what ideas you have...yes
 
  • #13
can u help me out?..i hav dis idea..
 
  • #14
I-Need-Help! said:
can u help me out?..i have dis idea..

make your own thread and someone will be able to help you
 
  • #15
okay thanx
 

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