You have a circular coil, and two metal plates a and b. The north pole of a bar magnet is moved away from the coil at a constant velocity(assume the bar magnet and the coil lies along the x axis). On which plate will the excess positive charge appear?
The Attempt at a Solution
Since the north pole is moved away, a south pole will be 'induced' in coil , which will result in a clockwise current, so a-b should behave as a cell with positive terminal a and negative terminal b. But my book says that excess positive charge will appear at b. Where am i wrong?[/B]
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