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Levitating a rod - magnetic field/forces

  1. Dec 2, 2007 #1
    1. The problem statement, all variables and given/known data

    What magnetic field strength will levitate the 2.0 g wire in the figure?


    2. Relevant equations

    F = ILB

    3. The attempt at a solution

    Solving for B, the formula becomes:

    B = F/(IL)

    F = 2*9.8 = 19.6
    IL = (1.5)*(0.10) = 0.15
    B= 19.6/0.015 = 130.666666666.....

    which comes out as incorrect

    what am i doing wrong?

  2. jcsd
  3. Dec 4, 2007 #2
    ...anybody know???

    lol i have to submit this in a few hours!! :(
    Last edited: Dec 4, 2007
  4. Dec 4, 2007 #3


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    Homework Helper

    convert the 2g to kg
  5. Dec 4, 2007 #4
    i was thinking of doing that...but i wasnt sure..but yea that is correct

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