Levitating a rod - magnetic field/forces

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Homework Help Overview

The discussion revolves around determining the magnetic field strength required to levitate a 2.0 g wire, with participants exploring the relevant equations and calculations involved in the problem.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the magnetic field strength using the formula B = F/(IL) but questions the correctness of their result. Some participants suggest converting the mass from grams to kilograms as a necessary step in the calculations.

Discussion Status

Participants are actively engaging with the problem, with one suggesting a conversion that may impact the calculations. There is a sense of urgency from the original poster due to an impending submission deadline.

Contextual Notes

The original poster's calculations are based on the assumption that the mass of the wire must be converted to kilograms for the formula to be applied correctly. The discussion reflects a need for clarity on unit conversions in the context of the problem.

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Homework Statement



What magnetic field strength will levitate the 2.0 g wire in the figure?

knight_Figure_32_36.jpg



Homework Equations



F = ILB


The Attempt at a Solution



Solving for B, the formula becomes:

B = F/(IL)

F = 2*9.8 = 19.6
IL = (1.5)*(0.10) = 0.15
B= 19.6/0.015 = 130.666666666...

which comes out as incorrect

what am i doing wrong?

thanks!
 
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...anybody know?

lol i have to submit this in a few hours! :(
 
Last edited:
convert the 2g to kg
 
i was thinking of doing that...but i wasnt sure..but yea that is correct

THANKS!
 

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