Light bent in gravitational field

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Light bends in a gravitational field due to the curvature of spacetime, as described by General Relativity (GTR). The bending of light is not dependent on the speed of the rocket; rather, it is determined by the gravitational influence of the Earth. When light is emitted from a rocket in free fall, it appears to bend relative to an observer on Earth, but not to the rocket itself. If there is no rocket and only a light source above the Earth, the light will still bend due to Earth's gravitational field. The trajectory of light is defined independently of other objects, and its path can be predicted based on its initial position and direction.
tomz
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i am new to GTR. Mytext book use an example to show ligt bendinf.
when a light release from the back of the rocket which goes around the earth, since the rocket is in free fall, light would not bent relative to the rocket, but bent relative to earth.

my problem is, is that means the amount of bending depend on the speed of the rocket?
if the rocket is very fast, than light would travel greater distance relative the earth, so there more bending?

If there is no rocket, but just a light source above the earth, would it bent at all?

Thank you...
 
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tomz said:
i am new to GTR. Mytext book use an example to show ligt bendinf.
when a light release from the back of the rocket which goes around the earth, since the rocket is in free fall, light would not bent relative to the rocket, but bent relative to earth.
The notion of whether a world-line is or is not curved (is or is not a geodesic) is defined independently of other world-lines. I think what's probably confusing you here is that you're imagining two trajectories in space, the rocket's and the light beams. These two trajectories are initially tangent, but later diverge. But the relevant notion is not a trajectory in space, it's a world-line in spacetime. The world-lines of the rocket and the light beam are *not* initially tangent.

It would indeed be a problem if two geodesics, initially tangent at a given point in spacetime, later diverged. But that isn't the case here.

tomz said:
my problem is, is that means the amount of bending depend on the speed of the rocket?
if the rocket is very fast, than light would travel greater distance relative the earth, so there more bending?

If there is no rocket, but just a light source above the earth, would it bent at all?

Nothing here depends on the source. Given the initial position and direction of motion of a ray of light, you can find its later motion.
 
In this video I can see a person walking around lines of curvature on a sphere with an arrow strapped to his waist. His task is to keep the arrow pointed in the same direction How does he do this ? Does he use a reference point like the stars? (that only move very slowly) If that is how he keeps the arrow pointing in the same direction, is that equivalent to saying that he orients the arrow wrt the 3d space that the sphere is embedded in? So ,although one refers to intrinsic curvature...

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