Light elements abundance in a static toy universe

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Discussion Overview

The discussion revolves around the theoretical implications of light element abundance, specifically hydrogen and helium, in a static universe. Participants explore the effects of stellar nuclear reactions and primordial nucleosynthesis on the mass proportions of these elements, considering the implications of a time-invariant cosmological model.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants inquire about the mass proportion of hydrogen to helium-4 in a static universe, questioning if it would resemble primordial nucleosynthesis proportions.
  • There is a suggestion that chemical abundances in primordial gas clouds would be difficult to explain if the universe were significantly older than current estimates.
  • One participant argues that a static universe cannot be described as "ancient," as it is time-invariant, and questions the relevance of certain comments regarding its age.
  • Participants discuss the assumption of starting with pure hydrogen and the role of stellar nuclear reactions in element transmutation.
  • Some propose that isotopes like helium-4, helium-3, and deuterium would be much rarer than observed, with most being locked in stars and consumed during stellar evolution.
  • There is a discussion about the steady state and static models, with some participants noting that in a true steady state model, the helium to hydrogen ratio would not change over time.
  • One participant raises the issue of how the neutron to proton ratio in a time-invariant universe would differ from that in primordial nucleosynthesis.
  • Another participant highlights that in a time-invariant universe, everything would eventually become iron, and questions the existence of chemical equilibrium among light elements.
  • There is a clarification that static and steady state models are different, with steady state models involving time dependency and expansion, while static models imply an equilibrium distribution independent of time.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the implications of a static universe on light element abundance. There is no consensus on the specifics of the elemental ratios or the nature of equilibrium in such a cosmological model.

Contextual Notes

Participants note the limitations of their discussion, including the dependence on definitions of static and steady state models, and the unresolved nature of certain assumptions regarding stellar nuclear reactions and equilibrium distributions.

TrickyDicky
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As an exercise in cosmology-fiction (I actually got curious about this from an actual cosmology textbook problem), taking into account the stellar nuclear reactions that involve the fusion of hydrogen into helium, what would (roughly) be the proportion (in mass) between Hydrogen and He-4 in a static universe?
Would it resemble the proportions of primordial nucleosynthesis given that these are produced close to thermodynamic equilibrium?
 
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Chemical abundances in 'pristine' [primordial] gas clouds would be very difficult to explain if the universe was significantly more ancient than we suspect. It is not uncommon that what you don't see tells you as much or more than what you do see.
 
Chronos said:
Chemical abundances in 'pristine' [primordial] gas clouds would be very difficult to explain if the universe was significantly more ancient than we suspect.
A static universe can't be more or less "ancient", it is symply time-invariant as a whole.
It is totally discarded by science so I'm not sure what your comment means. My question is purely theoretical.
 
Are you assuming that one begins with nothing but pure hydrogen, and that any transmutation was stellar in origin ?
 
BillSaltLake said:
Are you assuming that one begins with nothing but pure hydrogen, and that any transmutation was stellar in origin ?

Yes, just the stellar nuclear reactions, only in a static universe makes little sense to say what one begins with, since time is invariant.
 
Then 4He, 3He, and 2H would be much rarer than observed. Most of these isotopes would be inside active stars and would be consumed during the stars' lives. The initial collapse into stars would be different (I'm not sure of the details) because the initial gas would not be composed of a quarter 4He. I assume there would still be supernovae and metal enrichment, though. There would be probably 1/100 or less 4He than 1H, and most of that locked up in stars. Lower-mass stars (< ~1.5 solar masses) will usually become composed for a limited period of mostly 4He in later life, but this He will eventually fuse to heavier elements.
 
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BillSaltLake said:
Then 4He, 3He, and 2H would be much rarer than observed. Most of these isotopes would be inside active stars and would be consumed during the stars' lives. The initial collapse into stars would be different (I'm not sure of the details) because the initial gas would not be composed of a quarter 4He. I assume there would still be supernovae and metal enrichment, though. There would be probably 1/100 or less 4He than 1H, and most of that locked up in stars. Lower-mass stars (< ~1.5 solar masses) will usually become composed for a limited period of mostly 4He in later life, but this He will eventually fuse to heavier elements.
I guess you are ignoring that there is no global evolution in the kind of scenario I'm talking about. There can only be a permanent equilibrium distribution. I'm asking what would that distribution be according to the stellar nuclear reactions and core temperature conditions. Maybe it's easier to think in terms of proportion of neutrons and protons in thermodynamical equilibrium at the stars core temperatures.
 
The meaning of steady state might be a problem. After a very long time, everything might be photons and neutrinos (after black hole evaporation, and after any possible proton decay with the resulting positrons annihilating the existing electrons). I still doubt that the He could ever be over 1% of the H.
I'm assuming that H was distributed (with some density fluctuations) uniformly at the same density as baryonic matter now, and then it interacted, while the expansion factor remained constant. However, in a true steady state model, nothing would change, and the He:H ratio wouldn't change. There is no a priori equlibrium ratio unless there is a high-temp period or perhaps proton decay.
 
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BillSaltLake said:
The meaning of steady state might be a problem. After a very long time, everything might be photons and neutrinos (after black hole evaporation, and after any possible proton decay with the resulting positrons annihilating the existing electrons). I still doubt that the He could ever be over 1% of the H.
I'm assuming that H was distributed (with some density fluctuations) uniformly at the same density as baryonic matter now, and then it interacted, while the expansion factor remained constant. However, in a true steady state model, nothing would change, and the He:H ratio wouldn't change. There is no a priori equlibrium ratio unless there is a high-temp period or perhaps proton decay.

Steady state and static spacetime are different notions, the most known steady state universe , that of Gold, Bondi and Hoyle was an expanding spacetime, it wasn't static.
In static spacetimes there is no global change wrt time (although there may be locally).
There can be no periods nor "after a very long time"s. No expansion factor either and if you bother to look up some GR text no possibility for the existence of black holes, so no bh evaporation either. As anyone can see it is a completely unrealistic cosmology.

I'm only trying to learn something about stellar nuclear reactions in equilibrium and in a time invariant situation to contrast it with the factual primordial nucleosynthesis context and have a better understanding of it.
 
  • #10
Being more specific how much would the Nn/Np ratio in the time invariant situation in star's cores differ from the neutron freeze-out ratio in primordial nucleosynthesis (of around 1/6-1/7)?
 
  • #11
In any sort of time invariant universe, everything would end up as iron. The difficulty is that with light elements, there isn't a chemical equilibrium. Everything wants to be iron, and there are no cosmologically significant reverse reactions to break down iron into lighter elements.

However, this has been known since the 1940's, and the idea behind the steady state model was that there was a "magic source" of hydrogen to replace anything that got burned to He4. However, if we lived in a universe in which the magic source of hydrogen kept H/He ratios constant, we'd see no deuterium or He3, and a lot more Carbon-12 and heavier elements.

Being more specific how much would the Nn/Np ratio in the time invariant situation in star's cores differ from the neutron freeze-out ratio in primordial nucleosynthesis (of around 1/6-1/7)?

Very different. He4 to C12 has 1:1 and heavier elements are have more neutrons than proton culminating in neutron stars which are all neutrons.
 
  • #12
twofish-quant said:
In any sort of time invariant universe, everything would end up as iron. The difficulty is that with light elements, there isn't a chemical equilibrium. Everything wants to be iron, and there are no cosmologically significant reverse reactions to break down iron into lighter elements.

However, this has been known since the 1940's, and the idea behind the steady state model was that there was a "magic source" of hydrogen to replace anything that got burned to He4. However, if we lived in a universe in which the magic source of hydrogen kept H/He ratios constant, we'd see no deuterium or He3, and a lot more Carbon-12 and heavier elements.
For some reason you guys keep mixing static with eternal steady state models, even though I tried to clarify the difference in a previous post.
In steady state models there is time dependency, it is a expanding model. In static spacetimes nothing "ends up", there must be just an equilibrium distribution related to temperature, density and mass difference of protons and neutrons but independent of time.
 
  • #13
TrickyDicky said:
For some reason you guys keep mixing static with eternal steady state models, even though I tried to clarify the difference in a previous post.
In steady state models there is time dependency, it is a expanding model. In static spacetimes nothing "ends up", there must be just an equilibrium distribution related to temperature, density and mass difference of protons and neutrons but independent of time.

There can be no equlibrium as you envision it unless there is a two-way pathway. So in your hypothetical static universe you need to answer twofish's question about what moves things "uphill" from iron back to hydrogen. Otherwise the equilibrium distribution in the universe you are asking about is a universe filled with black holes and iron. The steady-state universe answers this by postulating continuous creation of hydrogen and expansion.
 
  • #14
phyzguy said:
There can be no equlibrium as you envision it unless there is a two-way pathway. So in your hypothetical static universe you need to answer twofish's question about what moves things "uphill" from iron back to hydrogen. Otherwise the equilibrium distribution in the universe you are asking about is a universe filled with black holes and iron. The steady-state universe answers this by postulating continuous creation of hydrogen and expansion.

What moves things "uphill" is the fact that in a static universe both ways of the two-way path have the same probability by definition, or at least that is what time-reversible reactions seem to imply.
 
  • #15
TrickyDicky said:
What moves things "uphill" is the fact that in a static universe both ways of the two-way path have the same probability by definition, or at least that is what time-reversible reactions seem to imply.

Clearly in the model you present there is no entropy and yes theoretically all reactions are time invariant so without entropy there would be no way to discern a 'direction' to time. To answer your question, in such a universe you can have whatever ratio of elements you like since all reactions are matched with their counterpart (or your universe won't remain static).
mathal
 
  • #16
mathal said:
Clearly in the model you present there is no entropy and yes theoretically all reactions are time invariant so without entropy there would be no way to discern a 'direction' to time. To answer your question, in such a universe you can have whatever ratio of elements you like since all reactions are matched with their counterpart (or your universe won't remain static).
mathal

Thanks for your input mathal, finally someone sees what I mean.
You are right, that was in fact my initial thought, that in such a universe any ratio would be possible, but I'm trying to introduce some constraints in the form of typical stellar core temperature , pressure and density and supposing the usual stellar nucleosynthesis reactions would also work so that some equilibrium distribution can be given that would make more sense than some other.
 
  • #17
An interstellar medium enriched by stellar ejecta would be anything but static. A universe without entropy would be not even wrong, but, I naively suspect it would remain in its original state. A universe without BB nuclosynthesis still needs a source of hydrogen for primordial stars to form. Once the stellar formation process began, the ISM would be continuously enriched by stellar ejecta. I fail to see how that could ever achieve equilibrium. It would merely continue to be enriched until so heavily metallized it could no longer support stellar fusion. The answer seems to be stars would not form in a universe without entropy.
 
  • #18
Chronos said:
An interstellar medium enriched by stellar ejecta would be anything but static. A universe without entropy would be not even wrong, but, I naively suspect it would remain in its original state.



A universe without BB nuclosynthesis still needs a source of hydrogen for primordial stars to form. Once the stellar formation process began, the ISM would be continuously enriched by stellar ejecta. I fail to see how that could ever achieve equilibrium. It would merely continue to be enriched until so heavily metallized it could no longer support stellar fusion. The answer seems to be stars would not form in a universe without entropy.

Exactly. This is merely a thought experiment. Objects like stars from our universe are not static- they age, things change, proportions of elements change with time. They couldn't exist in the form they have here. I find it hard to conceive of such a universe, the interrelationship of the laws that govern this universe are not workable without entropy. It is not that it is a physical law, merely that it is a consequence of the laws we operate under (in particular gravity).

You are thinking of primordial stars- our universe. The static universe TrickyDicky is presenting requires they just be here timelessly. An impossible requirement from my understanding of physics.
mathal
 
  • #19
An interstellar medium enriched by stellar ejecta would be anything but static. A universe without entropy would be not even wrong, but, I naively suspect it would remain in its original state. A universe without BB nuclosynthesis still needs a source of hydrogen for primordial stars to form. Once the stellar formation process began, the ISM would be continuously enriched by stellar ejecta. I fail to see how that could ever achieve equilibrium. It would merely continue to be enriched until so heavily metallized it could no longer support stellar fusion. The answer seems to be stars would not form in a universe without entropy.

mathal said:
Exactly. This is merely a thought experiment. Objects like stars from our universe are not static- they age, things change, proportions of elements change with time. They couldn't exist in the form they have here. I find it hard to conceive of such a universe, the interrelationship of the laws that govern this universe are not workable without entropy. It is not that it is a physical law, merely that it is a consequence of the laws we operate under (in particular gravity).

You are thinking of primordial stars- our universe. The static universe TrickyDicky is presenting requires they just be here timelessly. An impossible requirement from my understanding of physics.
mathal
Of course it is just a thought experiment, like the many that are used in science to get a better understanding of things, when Einstein imagines he is riding a photon no-one thinks about the practical impossibility of doing that. Many things are explained in physics thru thought experiment or ideal models that are known not to exist in reality.
Anyway a static universe doesn't imply there is no "local" change, it is just the global cosmological parameters as a whole that don't change wrt time.
Otherwise it would have been plain silly from Einstein and the physicist of their time to even consider static spacetimes as models for our universe knowing as it is obvious that locally things change.
 
  • #20
TrickyDicky said:
Otherwise it would have been plain silly from Einstein and the physicist of their time to even consider static spacetimes as models for our universe knowing as it is obvious that locally things change.
Remember that when Einstein postulated the static universe, he did not even know there was such a thing as nuclear fusion. After the Hubble flow was found and fusion was discovered, both which happened a decade later, it was quickly realized that the Big Bang model explained the H/He ratio in a universe of finite age. It wasn't until later still that all the other nuclei got explained, when the role of stars was appreciated!
 
  • #21
Ken G said:
Remember that when Einstein postulated the static universe, he did not even know there was such a thing as nuclear fusion. After the Hubble flow was found and fusion was discovered, both which happened a decade later, it was quickly realized that the Big Bang model explained the H/He ratio in a universe of finite age. It wasn't until later still that all the other nuclei got explained, when the role of stars was appreciated!
We have total agreement on this.
Could you address the thought experiment?
 
  • #22
TrickyDicky said:
We have total agreement on this.
Could you address the thought experiment?

Your thought experiment is basically, "In an imaginary universe where the known laws of physics do not apply, what would happen?"

The answer is, anything you want to happen. Since you have thrown the laws of physics out the window and made up your own laws of physics, we can't meaningfully speculate unless you tell us what laws of physics do apply.
 
  • #23
phyzguy said:
Your thought experiment is basically, "In an imaginary universe where the known laws of physics do not apply, what would happen?"

The answer is, anything you want to happen. Since you have thrown the laws of physics out the window and made up your own laws of physics, we can't meaningfully speculate unless you tell us what laws of physics do apply.

Well, let's say that all the known physics would be the same except that the global entropy of such imaginary universe would be constant. Almost all physical laws are time reversible anyway.
 
  • #24
While physical laws are generally time reversible, but, we have no meaningful evidence of time reversed processes. This is why we observe and do experiments. Just because something is mathematically possible does not mean it is physically meaningful - e.g., quadratic equations have two solutions, but, both are not necessarily meaningful.
 
  • #25
TrickyDicky said:
We have total agreement on this.
Could you address the thought experiment?
I mean that in a static universe, with stellar nucleosynthesis, there is no steady-state H/He ratio-- there isn't any H or any He (it's all iron, the most stable nucleus). So if Einstein had known about stellar nucleosynthesis, he would have never suggested a static universe, and he would have been spared the embarrassment of missing the dynamical solution of his equations. Indeed this is my greatest puzzle about Einstein's model-- even what was known about stars at the time should have been enough to rule it out. It was already known that stars convert gravitational energy to light, and we've never seen anything that takes light and turns it back into gravitational energy in any significant way. But this is all related to the big mystery of what allowed stars to exist as we see them in the first place, which no one knew at the time.
 
  • #26
Ken G said:
I mean that in a static universe, with stellar nucleosynthesis, there is no steady-state H/He ratio-- there isn't any H or any He (it's all iron, the most stable nucleus).

:rolleyes: I explained at least twice that my thought experiment was NOT an eternal steady-state universe.
 
  • #27
I don't quite understand the resistance to even consider this thought experiment, when actually all the classical tests of relativity are computed using a similarly unrealistic model (even more because it is supposed to be an empty universe): the static exterior of a non-rotating star. I see no nitpicking in this case because everyone understands it is an exact solution of the EFE that allows a valid local approximation however unphysical the model looks.
Well, the OP imaginary universe is certainly no EFE solution, and of course I didn't expect anything valid for our universe to come out of it, but all thought experiments allow certain divergence from physical reality. That is why they are thought experiments.
Mathal was right that in such universe, without constraining it in any way, every distribution would be valid, that is why I asked if it was possible to apply the known stellar nuclear reactions and core conditions to single out some more probable equilibrium distribution. Maybe the problem is not well-posed to single out a certain distribution but so far nobody has said so.
 
  • #28
TrickyDicky said:
In static spacetimes nothing "ends up", there must be just an equilibrium distribution related to temperature, density and mass difference of protons and neutrons but independent of time.

In that case, everything turns into iron. The problem with that sort of universe is that it's pretty boring. Everything is iron. Stars don't exist.

Nuclear statistical equilibrium is pretty independent of temperature, density, and mass for normal temperatures. The equilibrium distributions will change only once you reach "nuclear" temperatures and densities. Anything less than that, it's 100% iron.

So now that question one has been set up, I'd like to make a universe that's slightly more interesting.
 
  • #29
TrickyDicky said:
I don't quite understand the resistance to even consider this thought experiment

There isn't. The problem is that I've mentioned the result of the thought experiment. Everything turns into iron. Once you have specified a density, temperature, and electron fraction, then there are lots of people that have calculated the "equilibrium state" of matter.

http://user.numazu-ct.ac.jp/~sumi/eos/

It will change for high temperatures and densities (i.e. T>1 million kelvin rho > 10^7 g/cm^2) but for anything under that, it's 100% iron nuclei. For high densities it start going to neutronium and maybe quark soup. For high temperatures, it starts turning into nucleon gas if it gets really hot.

I asked if it was possible to apply the known stellar nuclear reactions and core conditions to single out some more probable equilibrium distribution. Maybe the problem is not well-posed to single out a certain distribution but so far nobody has said so.

The answer is 100% iron.

Next question?
 
  • #30
twofish-quant said:
In that case, everything turns into iron. The problem with that sort of universe is that it's pretty boring. Everything is iron. Stars don't exist.
That answer is valid for a strictly time-dependent universe. You are not bothering to answer what I'm asking.

twofish-quant said:
Nuclear statistical equilibrium is pretty independent of temperature, density, and mass for normal temperatures.

stellar core temperature is normal temperature to you?
 

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