Light Interference Webassign question

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Homework Help Overview

The problem involves light interference using two glass plates with a specific separation created by a wire. The task is to determine the number of bright fringes that appear along the length of the plates, given the wavelength of the light and the dimensions of the setup.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the thickness and the maximum value of m in the interference equation. There is confusion regarding the starting point for m and how it affects the total count of bright fringes.

Discussion Status

Some participants have provided guidance on interpreting the values of m and how to count them correctly. There appears to be a productive exchange regarding the implications of starting m at zero and how that affects the final answer.

Contextual Notes

Participants are navigating the constraints of the problem, including the specific values for wavelength and dimensions, as well as the expectations set by the homework platform.

nickredsox
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Homework Statement



Light of wavelength 525 nm is used to illuminate normally two glass plates 26 cm in length that touch at one end and are separated at the other end by a wire of radius 0.03 mm. How many bright fringes appear along the total length of the plates?

Homework Equations



2*t=(m+1/2)*wavelength

The Attempt at a Solution


I thought t would be .6 since that would be the diameter. Then I solved for m and got 228. However webassign doesn't like this answer and I am not really sure how to go about this problem
 
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You solved for the maximum value of m, but realize that m starts at zero.
 
im not really understanding because if i solve for t when m=0 if i plug it back in and solve for m I am just going to get 0
 
You're missing my point. The values of m: 0, 1, 2, 3, 4... If the maximum value of m = 4 (pretend), then how many values of m are there?
 
there would be five. so for my answer it should be one more than the answer i already got (228)?
 
That's what I would put.
 
thank you a lot it worked
 

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