Light - Thin Film interference

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Homework Help Overview

The problem involves a thin film of magnesium fluoride (MgF2) with a refractive index of 1.38, which is coated on glass. Constructive interference is observed for light wavelengths of 500 nm and 625 nm, and the task is to determine the thinnest film thickness for this interference to occur.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of equations for constructive interference and question the appropriateness of the formulas used for the given wavelengths.
  • Some participants explore the relationship between the thickness for each wavelength and suggest using different integer values for the order of interference (m values) to find a common thickness.
  • There is a focus on deriving a relationship between the two m values based on the thickness equations.

Discussion Status

The discussion has progressed through various attempts to find a common thickness for both wavelengths. Some participants have provided insights into the relationships between m values, while others have questioned the correctness of their approaches. There is a recognition of the need to find the smallest integers that satisfy the derived relationships, indicating a productive direction in the discussion.

Contextual Notes

Participants note that the index of refraction of glass is greater than that of MgF2, which influences the equations used for interference. There is also an emphasis on ensuring that the m values used in calculations are appropriate for the problem context.

Foxhound101
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Homework Statement


A thin film of MgF2 with n = 1.38 coats a piece of glass. Constructive interference is observed for the reflection of light with wavelengths of 500 nm and 625 nm.

Part A -
What is the thinnest film for which this can occur?

Homework Equations


t = lambda/2n *(m + .5)
and/or
lambda=(2*n*t)/(m+.5)


The Attempt at a Solution


Not sure what I am supposed to do, because of the two wavelengths. I know what to do for a single wavelength...

So this is my work for solving the problem with each wavelength

m=0,1,2,3,...

500 = 2(1.38)(t)/(m+.5)

500(0+.5) = 2.76(t)

t = 90.6

and

625(0+.5) = 2.76(t)
t = 113

Now that I have done this, I am not sure how to proceed. Any help is appreciated.
 
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Hi Foxhound101,

Foxhound101 said:

Homework Statement


A thin film of MgF2 with n = 1.38 coats a piece of glass. Constructive interference is observed for the reflection of light with wavelengths of 500 nm and 625 nm.

Part A -
What is the thinnest film for which this can occur?

Homework Equations


t = lambda/2n *(m + .5)
and/or
lambda=(2*n*t)/(m+.5)

I don't think these are correct. I believe these equations would be for destructive interference; isn't the index of refraction of glass greater than 1.38?

The Attempt at a Solution


Not sure what I am supposed to do, because of the two wavelengths. I know what to do for a single wavelength...

So this is my work for solving the problem with each wavelength

m=0,1,2,3,...

500 = 2(1.38)(t)/(m+.5)

500(0+.5) = 2.76(t)

t = 90.6

and

625(0+.5) = 2.76(t)
t = 113

Now that I have done this, I am not sure how to proceed. Any help is appreciated.

By setting m=0, you have found a minimum thickness for each wavelength (for destructive interference with the equations you are using). But in this problem you don't want the minimum for each; you want a thickness t that is true for both wavlengths. So use m1 for one wavelength and m2 for another wavelength.

After eliminating t, you can find a relationship between the two m values. What do you get?
 
Thanks for the help, alphysicist

<i>isn't the index of refraction of glass greater than 1.38?</i> Index of refraction in glass is greater than 1.38...the value is sometimes 1.55

So...another formula I have is t=(m*lambda)/(2n)

So...
lambda = 500

t=(1*500)/(2*1.38)
t= 181

t= (2*500)/(2*1.38)
t= 362

lambda = 625
t = (1*625)/(2*1.38)
t = 226

t = (2*625)/(2*1.38)
t = 453
 
So the relationship between these values...

181/226 = .8

362/453 = .8

Interesting...so what do I do, now that I know this relationship?
 
Foxhound101 said:
Thanks for the help, alphysicist

<i>isn't the index of refraction of glass greater than 1.38?</i> Index of refraction in glass is greater than 1.38...the value is sometimes 1.55

So...another formula I have is t=(m*lambda)/(2n)

That's the right formula for this problem. (If, for example, the thin film was on something that with an index of refraction less than 1.38, then your original problem would have been correct for constructive interference.)

So...
lambda = 500

t=(1*500)/(2*1.38)
t= 181

t= (2*500)/(2*1.38)
t= 362

lambda = 625
t = (1*625)/(2*1.38)
t = 226

t = (2*625)/(2*1.38)
t = 453


I don't think this is the way you want to do it. You are setting the m's to be specific numbers; but in this problem they are unknown. Just leave them as m1 and m2:

t=(m1*500)/(2*1.38)

t = (m2*625)/(2*1.38)

So you have these two equations; now eliminate t to find out how the two m values are related. For example, if you end up with:

m1 = 1.7 m2

then you know that m1=17, m2=10 would be the smallest integer values that m1 and m2 could have that still obey that relationship.



(The ratios you found in your last post are related to this, but I think it rather hides the process.)
 
t=(m*500)/2.76
t=(m*625)/2.76

(m1*500)/2.76 = (m2*625)/2.76
m1 * 500 = m2 * 625

m1 = .8m2

m1 = 10 and m2 = 8
 
Plugging those m's in...

t = (10*500)/(2.76)
t = 1812

t = (8*625)/(2.76)
t = 1812

Does this seem like a good answer? I typed 1810 into the program and it told me I was still wrong.
 
Foxhound101 said:
t=(m*500)/2.76
t=(m*625)/2.76

(m1*500)/2.76 = (m2*625)/2.76
m1 * 500 = m2 * 625

m1 = .8m2

m1 = 10 and m2 = 8

I think you have those backwards (m1 is 8 and m2 is 10).

However, those are not the smallest integers that satisfy the relationship. (Rewrite 0.8 as a fraction and then simplify.)

Once you get the set of smallest integers, what do you get for the minimum thickness?
 
If I change m1 and m2, then they won't equal each other.

If I leave m1 = 5 and m2 = 4 then I get...

(5*500)/2.76
t = 906

t=(4*625)/2.76
t = 906

This seems like a decent answer...answers for other problems were t=1000ish, so this is decent.

Does this seem like a good answer now?
 
  • #10
Foxhound101 said:
If I change m1 and m2, then they won't equal each other.

Okay, I see what happened. You wrote

m1 = .8m2

a few posts ago but you meant

m2 = .8m1

So your numbers for m1 and m2 are fine.

If I leave m1 = 5 and m2 = 4 then I get...

(5*500)/2.76
t = 906

t=(4*625)/2.76
t = 906

This seems like a decent answer...answers for other problems were t=1000ish, so this is decent.

Does this seem like a good answer now?

That looks right to me (if they want the answer in nanometers).
 
  • #11
That was the correct answer. Thank you for your help.
 
  • #12
Sure, glad to help!
 

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