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Lim x to 0 (1/sinx - 1/x ) is equals to infinity?

  1. Feb 13, 2006 #1
    may i know is it lim x to 0 (1/sinx - 1/x ) is equals to infinity??
     
  2. jcsd
  3. Feb 13, 2006 #2

    TD

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    You cannot apply L'Hospital on this function (yet), you'd need to rewrite it so that you get something of the form 0/0 or ∞/∞.
     
  4. Feb 13, 2006 #3
    To apply L'Hospital's Rule, put the expression in theform f(x)/g(x). If the form is indeterminate, then you can apply the Rule.
     
  5. Feb 13, 2006 #4

    TD

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    Just to avoid confusion: it has to be 0/0 or ∞/∞ as I said, since there are more indeterminate forms possible. Many can be reduced to one of the two 'allowed' ones to use the rule though.
     
  6. Feb 13, 2006 #5
    okok.thanx
     
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