teng125
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may i know is it lim x to 0 (1/sinx - 1/x ) is equals to infinity??
The discussion revolves around the limit of the expression (1/sin(x) - 1/x) as x approaches 0, specifically questioning whether it equals infinity. The subject area is calculus, focusing on limits and indeterminate forms.
Some participants have provided guidance on rewriting the expression to achieve the necessary form for L'Hospital's Rule. There is an ongoing exploration of the conditions for applying this rule, but no consensus has been reached regarding the limit itself.
There is an emphasis on the requirement for the expression to be in the form of 0/0 or ∞/∞ to apply L'Hospital's Rule, indicating a focus on understanding the conditions for limit evaluation.
Just to avoid confusion: it has to be 0/0 or ∞/∞ as I said, since there are more indeterminate forms possible. Many can be reduced to one of the two 'allowed' ones to use the rule though.daveb said:To apply L'Hospital's Rule, put the expression in theform f(x)/g(x). If the form is indeterminate, then you can apply the Rule.