Limit as x approaches 1 of integral of sin(t) over x squared minus 1

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SUMMARY

The discussion centers on evaluating the limit of the expression \(\frac{\int_{1}^{x} \sin(t) \, dt}{x^2 - 1}\) as \(x\) approaches 1. Participants clarify that the variable of integration is \(t\), while \(x\) is the limit of integration and also appears in the denominator. As \(x\) approaches 1, both the numerator and denominator approach 0, indicating the need for L'Hôpital's Rule to resolve the indeterminate form.

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[tex]\frac{\int_{1}^{x} sint dt}{x^2-1}[/tex]
 
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Is it t or x inside integral and the denominator is below the "whole" integral?
 
any ideas? what can you say about the numerator & denominator as x tends to 1?
 
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