Limit of f(x) as x tends to 0 for f(x)=[sinx]/[x^2]

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SUMMARY

The limit of the function f(x) = sin(x)/x^2 as x approaches 0 is an indeterminate form of 0/0. To resolve this, one must apply l'Hôpital's rule or recognize the limit of sin(x)/x, which equals 1 as x approaches 0. Thus, the limit can be rewritten as lim (x → 0) (sin(x)/x) * (1/x), leading to the conclusion that the limit does not exist due to the divergence of 1/x as x approaches 0.

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  • Understanding of limits in calculus
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  • Knowledge of l'Hôpital's rule
  • Basic algebraic manipulation of limits
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Homework Statement



Does f(x) tend to a limit as x tends to 0?

Homework Equations



f(x)=[sinx]/[x^2]

The Attempt at a Solution



Well i sinx would tend to zero and so would x^2, so would the limit just be zero?
 
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No, 0/0 is an indeterminant form. It means you have to work harder. Do you know the limit of sin(x)/x? Do you know l'Hopital's rule?
 
Do you know that:
\lim_{x \rightarrow 0}\frac{sinx}{x}=1

?
 
\frac{sin(x)}{x^2}= \left(\frac{sin(x)}{x}\right)\left(\frac{1}{x}\right)
 

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