MHB Limit in Infinity: Check Results Now

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The discussion revolves around evaluating two limits, where one participant initially calculated e^3/0, mistakenly interpreting it as e^(infinity). They later corrected their error, confirming that the first limit should yield e^3, while the second limit correctly results in e^(-5/2) as verified by Wolfram Alpha. The conversation highlights the importance of accurate calculations in limit evaluations. The participant expresses gratitude for the clarification regarding their mistake. Overall, the thread emphasizes the significance of double-checking mathematical results.
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According to wolfram alpha you should get $e^3$ for the first limit and indeed $e^{\frac{-5}{2}}$ for the second one.
 
Oh yes it is 3 I made mistake with dividing, ty
 

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