Limit of a sequence in a closed interval is in that interval

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SUMMARY

The limit of a sequence {xn} that is contained within a closed interval [a,b] converges to a point x that also lies within the interval [a,b]. This conclusion is derived from the properties of bounded sequences and the definition of limits. Specifically, since the sequence is bounded, the limit must also fall within the bounds of the interval. A proof by contradiction can be effectively employed to demonstrate that assuming x is outside [a,b] leads to a contradiction.

PREREQUISITES
  • Understanding of closed intervals in real analysis
  • Familiarity with the definition of limits
  • Knowledge of bounded sequences
  • Experience with proof techniques, particularly proof by contradiction
NEXT STEPS
  • Study the properties of closed intervals in real analysis
  • Learn about the formal definition of limits in calculus
  • Explore the concept of bounded sequences and their implications
  • Practice proof by contradiction with various mathematical statements
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Students of real analysis, mathematicians, and educators looking to deepen their understanding of limits and sequences within closed intervals.

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Homework Statement


Suppose [a,b] is a closed interval (on R), and {xn}n>=1 is a sequence such that
a) xn belongs to [a,b]
b) lim as n--> infinity xn = x exists
prove x belongs to [a,b]


Homework Equations





The Attempt at a Solution



Well since any sequence is bounded, then obviously the limit has to be within the bounds.

Not sure where to begin though. I'm thinking of using the definition of a limit..? For all k>0, there exists a natural # N such that for all n>=N, |x-xn|<k
Or that this is Cauchy since it is bounded ?

Just not exactly how to go about showing that x is in that interval!
 
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I would do a proof by contradiction. Assume x is outside of [a,b]. Isn't it pretty easy to derive a contradiction?
 

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