Limit of function of several variable

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SUMMARY

The limit of the function f(x, y) = x²y / (2x³ - y³) as (x, y) approaches (0, 0) can be evaluated using various paths. The discussion highlights that evaluating limits along the axes, such as f(x, 0) and f(0, y), yields a limit of 0. However, to rigorously prove the existence of the limit, an epsilon-delta proof is required. Additionally, finding a path that results in a different limit can demonstrate that the limit does not exist.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with epsilon-delta definitions of limits
  • Ability to analyze limits along different paths
  • Knowledge of continuity in multivariable functions
NEXT STEPS
  • Study epsilon-delta proofs in detail
  • Learn about path-dependent limits in multivariable calculus
  • Explore examples of limits that do not exist
  • Review the section on limits and continuity in multivariable calculus on Wikipedia
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Students studying multivariable calculus, educators teaching calculus concepts, and anyone interested in understanding the behavior of limits in multiple dimensions.

violette
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Homework Statement



lim(x,y)->(0,0) x2y / 2x3-y3

Homework Equations





The Attempt at a Solution


I found lim f(x,0)=0 and lim f(0,y)=0.So i assume limit exists and equals 0?
I would like to get some tips on how to solve this type of problems?Do I always find f(x,0) and f(0,y)?Because I always seem to get 0 as the answer when I do that.

Thanks in advance =)
 
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Try taking the limit along the line x=y. There are more than two ways for (x,y) to approach (0,0).
 
hi thanks!
means I can try any ways in hope that one way will prove that limit does not exist?
how can i prove that limit exist then?
thanks =)
 

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