Limit of Series: Find Out How (N+1)/(2N+1) = 1/2

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Homework Help Overview

The discussion revolves around finding the limit of the expression (N+1)/(2N+1) as N approaches infinity, specifically addressing why this limit equals 1/2. The subject area is calculus, focusing on limits and rational functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various methods to evaluate the limit, including L'Hôpital's rule, analyzing coefficients, and dividing by the highest power of N. Some question the assumptions behind these methods and the implications of the results.

Discussion Status

The discussion includes multiple approaches to the limit, with participants sharing different techniques and reasoning. While no consensus is reached, several methods are presented, and some participants express appreciation for the variety of approaches discussed.

Contextual Notes

Participants note the presence of an indeterminate form when substituting N with infinity, which leads to the exploration of different limit evaluation techniques. There is also mention of the intuitive understanding of the limit converging to 1/2.

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can someone please explain to me how the limit of (N+1)/(2N+1) as N goes to infinity is equal to 1/2? i know this is really simple, but I'm pretty rusty on this stuff.
 
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If you substitute [tex]N=\infty[/tex] you will get undetermined form [tex]\frac{\infty}{\infty}[/tex]. So you can L' Hospital rule, i.e, differentiate numerator and denominator (individually) with respect to N and then take limit for the resulting expression.
 
When both the top and bottom go to infinity you can look at the coefficients in front of the variable.
 
When you have a rational function of N, you can divide the numerator and denominator by the highest power of N. In your case:

[tex] \lim_{N \to \infty} \frac{N+1}{2N+1} =\lim_{N \to \infty} \frac{(1/N)(N+1)}{(1/N)(2N+1)} = \lim_{N \to \infty} \frac{1+1/N}{2 + 1/N} = \frac{1 +0}{2 +0} = \frac{1}{2}[/tex]

since [itex]\lim_{N\to \infty} 1/N = 0[/itex].
 
It's probably easier to just stick in limits and cancel out the irrelevant details to leave just the numerator and denominator as 1 and 2, slightly shorter process if less robust ie n+1/n+1 in both the numerator and denominator =1 with appropriate limits. That was the way I was taught but the answer above is completely correct. It's intuitively correct to if you can imagine them both converging in an iterative way ie for every value of n the answer is converging to 1/2 in an infinite series.

Sorry nice to see a new way of doing something that is more rigid just pop corn posting in case it gets even more interesting.
 
Last edited:
thank you all
 

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