Undergrad Limit of the product of these two functions

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SUMMARY

The limit of the product of two functions, where one function approaches zero and the other is a bounded oscillating function like g(x) = sin(x), is established as zero. Specifically, if limx → ∞ f(x) = 0 and g(x) is bounded, then limx → ∞ f(x)g(x) = 0. This result can be derived using the Squeeze theorem, which is a fundamental concept in calculus. While the discussion references sequences, the theorem applies equally to functions.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with the Squeeze theorem
  • Knowledge of bounded functions
  • Basic concepts of epsilon-delta proofs
NEXT STEPS
  • Study the Squeeze theorem in detail
  • Review calculus textbooks for theorems on limits of products
  • Explore epsilon-delta definitions of limits
  • Investigate bounded functions and their properties
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in advanced limit theorems and their applications in analysis.

LagrangeEuler
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If we have two functions ##f(x)## such that ##\lim_{x \to \infty}f(x)=0## and ##g(x)=\sin x## for which ##\lim_{x \to \infty}g(x)## does not exist. Can you send me the Theorem and book where it is clearly written that
\lim_{x \to \infty}f(x)g(x)=0
I found that only for sequences, but it should be correct for functions also.
 
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LagrangeEuler said:
If we have two functions ##f(x)## such that ##\lim_{x \to \infty}f(x)=0## and ##g(x)=\sin x## for which ##\lim_{x \to \infty}g(x)## does not exist. Can you send me the Theorem and book where it is clearly written that
\lim_{x \to \infty}f(x)g(x)=0
I found that only for sequences, but it should be correct for functions also.
If ##g## is any bounded function then there is a straightforward epsilon-delta proof.
 
|f(x)g(x)| is bounded by |f(x)| goes to 0
 
I don't know of a specific place that states this exact problem, but this is an application of the Squeeze theorem which can be found in any calculus textbook.
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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