Limit of x^1/x as x Approaches Infinity: Simplified Using ln and e

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Homework Help Overview

The discussion revolves around evaluating the limit of the expression x^(1/x) as x approaches infinity, with a focus on using logarithmic properties and the exponential function.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the transformation of the limit using natural logarithms and the exponential function, with one participant suggesting rewriting the limit as e^(ln(x)/x).

Discussion Status

The conversation includes attempts to simplify the limit, with one participant noting that the limit of (ln(x)/x) approaches 0, leading to the conclusion that e^0 equals 1. However, the discussion does not reach a formal consensus on the overall limit evaluation.

Contextual Notes

No specific constraints or missing information are noted in the discussion.

golriz
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Hello
please help me and compute this limit:
llim x^1/x when x approaches infinite.
I think we can rewrite this so: e^ln (x^1/x).
 
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ok so it simplifies to e^((lnx)/x) and the limit of (lnx)/x is 0, so? e^0 = 1
 
thanks
 
thanks
it was very easy!:smile:
 

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