Limit proof of trigonometric function

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Homework Statement



Prove that limh→0[(cos(h-1))/h]=0.

Homework Equations



Half angle formula
From an example:

limh→0[(cos(h-1))/h] = limh→0[-(2sin2(h/2))/h]

They state that they use the half-angle formula in the following way:

cosh= 1-2sin2(h/2)

I'm not really sure how they are getting this from the half angle formula. Any pointer in the correct direction would be greatly appreciated. Thank you, in advance.
 
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Thank you, very much! Somehow I didn't notice to split cos(h) into cos(h/2 + h/2).