Line element in spherical coordinates

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The discussion clarifies the line element in spherical coordinates, expressed as ds^2 = dr^2 + r^2(dθ^2 + sinθ dφ), emphasizing that it measures the distance between two arbitrary points rather than just from the origin. The transformation from Cartesian coordinates is highlighted, showing how the differentials dx, dy, and dz lead to the more complex expression for ds^2. This approach illustrates that simply using dr^2 does not account for the angular components necessary in spherical geometry. Understanding this distinction is crucial for grasping concepts in general relativity and astrophysics. The explanation reinforces the importance of considering both radial and angular distances in spherical coordinates.
broegger
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Hi,

I was just reading up on some astrophysics and I saw the line element (general relativity stuff) written in spherical coordinates as:

ds^2 = dr^2 + r^2(d\theta^2 + \sin\theta\d\phi)​

I don't get this. dr is the distance from origo to the given point, so why isn't ds^2 = dr^2 without the other stuff?
 
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broegger said:
I don't get this. dr is the distance from origo to the given point, so why isn't ds^2 = dr^2 without the other stuff?

Because you aren't after the distance between some point and the origin, you're after the distance between 2 arbitrary points in space. If you want to see how this expression comes about then start from the more intutive expression for the line element in Cartesian coordinates:

ds^2=dx^2+dy^2+dz^2

Then use the following transformation equations:

x=r\sin(\theta)\cos(\phi)
y=r\sin(\theta)\sin(\phi)
z=r\cos(\theta)

Take the differentials dx, dy, and dz and verify that ds^2 \neq dr^2 in general.
 
Last edited:
Thanks, Tom!
 

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