Line element in spherical coordinates

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SUMMARY

The discussion focuses on the line element in spherical coordinates as expressed in general relativity. The correct formulation is given by ds² = dr² + r²(dθ² + sin²θ dφ²), which accounts for the distance between two arbitrary points in space rather than just from the origin. The transformation from Cartesian coordinates is essential for understanding this expression, utilizing the equations x = r sin(θ) cos(φ), y = r sin(θ) sin(φ), and z = r cos(θ). The conclusion emphasizes that ds² cannot be simplified to dr² alone.

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broegger
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Hi,

I was just reading up on some astrophysics and I saw the line element (general relativity stuff) written in spherical coordinates as:

ds^2 = dr^2 + r^2(d\theta^2 + \sin\theta\d\phi)​

I don't get this. dr is the distance from origo to the given point, so why isn't ds^2 = dr^2 without the other stuff?
 
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broegger said:
I don't get this. dr is the distance from origo to the given point, so why isn't ds^2 = dr^2 without the other stuff?

Because you aren't after the distance between some point and the origin, you're after the distance between 2 arbitrary points in space. If you want to see how this expression comes about then start from the more intutive expression for the line element in Cartesian coordinates:

ds^2=dx^2+dy^2+dz^2

Then use the following transformation equations:

x=r\sin(\theta)\cos(\phi)
y=r\sin(\theta)\sin(\phi)
z=r\cos(\theta)

Take the differentials dx, dy, and dz and verify that ds^2 \neq dr^2 in general.
 
Last edited:
Thanks, Tom!
 

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