The forum discussion centers on the line integral of the function (xe^y) along the curve defined by x=e^y. The integral is computed as (1/3)e^3y + C, with the solution involving the integral of (xe^y)((e^y)^2 + 1)^(1/2). The user seeks clarification on the handling of the 1/2 exponent during the integration process, indicating a common point of confusion in evaluating integrals involving exponential functions.
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winter_ken said:Homework Statement
Integrate some area C of (xe^y)ds where C is the arc of the curve x=e^y
Homework Equations
What is the indeffinite integral and why is it that? Answer is (1/3)e^3y + C
The Attempt at a Solution
Integral of (xe^y)((e^y)^2 + 1)^(1/2)
= Integral of (e^2y)(e^2y + 1)