Line of maximum for a 2D 'surface'

Click For Summary
SUMMARY

The discussion focuses on determining the maximum line of a 2D surface represented by the expression [(1 + β/n)^ n * (1 + n/β)^ β] / 2^(n+β), where n and β are integers greater than 1. The user seeks to prove that this expression is always less than 1 when n is not equal to β, and equals 1 when n equals β. The analysis involves asymptotic behavior of Bessel and Hankel functions, which are critical in understanding the limits of this mathematical expression.

PREREQUISITES
  • Understanding of asymptotic analysis in mathematical functions
  • Familiarity with Bessel functions and Hankel functions
  • Basic knowledge of limits and inequalities in calculus
  • Experience with 2D surface analysis in mathematical contexts
NEXT STEPS
  • Research the properties of Bessel functions and their asymptotic behavior
  • Study inequalities involving exponential functions and their limits
  • Explore techniques for analyzing 2D surfaces in mathematical optimization
  • Learn about the application of Hankel functions in complex analysis
USEFUL FOR

Mathematicians, researchers in applied mathematics, and students studying advanced calculus or mathematical analysis, particularly those interested in Bessel and Hankel functions.

Karthiksrao
Messages
66
Reaction score
0
Hello,

I hope this is the right section to post this question.

While analysing the asymptotic value of a ratio of a bessel and a hankel function, I reduced it to something of the form

[(1 + β/n)^ n * (1 + n/β)^ β] / 2^(n+β) ; n and β are integers and greater than 1

how do I show that the above expression is always less than 1, for n≠β. When n=β, the above expression becomes equal to 1.

Or relatedly, if I have to find the line of maximum for a 2D surface given above (for varying n and β), how do I go about ?

Thanks!
 
Physics news on Phys.org

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K