Line tension problem help

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drkidd22
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I need help trying to figure this problem out.
 
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Hi drkidd22! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
So I have this so far trying to find Tbd.
It will be the same for Tbe as they are the same distance away from A.
 
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distance on horizontal=√(18^2+18^2)=18*√2 ft
distance on vertical=21 ft
∴θ=angle in between pole & cable=tan-1(18*√2/21)=50.479 degree
Σall horizontal force=0
1680=2T sinθ
∴T=1088.944 lb
Σall vertical force =0
R=2T cosθ [R= reaction force at A ]
∴R=1385.924 lb

Not sure if it's correct
 
How many components are there to the reaction at A (at most)? You ask if it is correct. But you could determine this yourself by recognising that there are at most 6 equilibrium equations for the whole thing...
 
So have you calculated any of them so far?

(By the way your physicsp148.doc document has just one line and it is sloppy, or incorrect or inconsistent. If T is a force, why do the units have ft at the end?)
 
when you say "1680=2T sinθ ", exactly what free body diagram are you considering the equilibrium of?