Linear Algebra Eigenvector Properties

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SUMMARY

The discussion centers on the properties of eigenvectors in relation to matrix addition. It is established that if matrices A and B share the same eigenvector X, then X is also an eigenvector of the sum A+B. Additionally, the claim that the eigenvalues of A and B can be summed to find the eigenvalue of A+B is false; a counterexample demonstrates that the eigenvalue of A+B does not equal the sum of the eigenvalues of A and B. The confusion in the wording of the problem is noted, but the mathematical principles are clarified through proof.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with matrix operations and properties
  • Knowledge of linear algebra concepts
  • Ability to construct mathematical proofs
NEXT STEPS
  • Study the properties of eigenvectors in matrix addition
  • Learn about counterexamples in linear algebra
  • Explore the implications of eigenvalues in linear transformations
  • Investigate the spectral theorem and its applications
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Students of linear algebra, mathematicians, and educators seeking to deepen their understanding of eigenvector properties and their implications in matrix theory.

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Homework Statement



True/False: If true give a proof, if false give a counterexample.
a)
If A and B have the same eigenvector X, then A+B should also have the same eigenvector, X.
b)
if A has an eigenvalue of 2, and B has an eigenvalue of 5, then 7 is an eigenvalue of A+B




Homework Equations





The Attempt at a Solution



for b):
2 0 2 3
0 2 has eigenvalue of 2; 3 2 has eigenvalue of 5

When I add them together (A+B) you get 4 3
3 4

Then I found an eigenvalue of 7; Is this correct?
Or the property of A+B != eigenvalueA + eigenvalueB is always correct? But this question's wording is kind of weird, because it said if its true give a counterexample ...


for a) I think it is false,...not entirely sure though.
 
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FinalStand said:
True/False: If true give a proof, if false give a counterexample.



But this question's wording is kind of weird, because it said if its true give a counterexample ...

That's not what I read.
 
Ok I am stupid, I read the question wrong so I confused myself...here goes my mark...
 
(a) asks you to show that If X is an eigenvector for both A and B then it is an eigenvector for A+ B. If X is an eigevector of A, then AX= \lambda_A X for some number \lambda_A. If X is an eigenvector of B, then BX= \lambda_B X for some number \lambda_B. Now, what can you say about (A+ B)X?
 

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