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(1) v is also an eigenvector of 2A

(2) v is also an eigenvector of A^2

(3) v is also an eigenvector of A^-1

A) 1 only

B) 2 only

C) 3 only

D) 1 and 3 only

E) 1,2 and 3

I am pretty sure 2 is true because if we look at Av = (lamba)v.

A^2v = A(lambda)v = (Av)(lambda) = (lambda)v(lambda) = (lambda)^2 v

So A^2v = (lambda)^2v. So that should be that v is an eigenvector for A^2 as well. I am not sure about the others can someone help?