Linear algebra matrices multiplication (transpose)

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The discussion focuses on finding the matrix A through the properties of transposes in linear algebra. The relevant equation used is (A^transpose)^transpose = A, which is applied to simplify the expression involving the matrix. The initial matrix provided is [[-5, 0], [-8, -7]]. Participants work through the steps of transposing and manipulating the matrix to arrive at a solution. Ultimately, the process leads to a clearer understanding of matrix operations and their implications.
dmoney123
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Homework Statement



We are looking for the matrix A

Homework Equations



(A^transpose)^transpose=A

The Attempt at a Solution



i would start with finding the transpose of the matrix.

-5 0
-8 -7
 

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dmoney123 said:

Homework Statement



We are looking for the matrix A

Homework Equations



(A^transpose)^transpose=A

The Attempt at a Solution



i would start with finding the transpose of the matrix.

-5 0
-8 -7

OK, so
((2A - I)^T)^T = \begin{bmatrix}-5&0\\-8&-7\end{bmatrix}

Now what? Use your relevant equation to simplify the left side.
 
S0 + identity matrix on left side... =

[-4 0] ... then /2= [-2 0]
-8 -6 ......-4 -3

GOT IT!
 
Last edited:

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