Linear Algerbra. Inverses and Algerbraic Properties of Matrices

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SUMMARY

The discussion focuses on solving the equation C^{T}B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=C^{T} for the invertible matrices A, B, C, and D, all of size n x n. Participants emphasize the importance of systematically "undoing" operations applied to D by manipulating the equation step-by-step. The initial step involves left-multiplying by (C^T)^{-1} to simplify the equation to B^{-1}A^{-2}BAC^{-1}DA^{-2}B^TC^{-2}=I. Further steps include left-multiplying by B and right-multiplying by C^2 to isolate D.

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  • Proficiency in solving linear algebra equations involving multiple matrices.
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stumpoman
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Homework Statement


Assuming that all matrices, A, B, C, and D, are n x n and invertible, solve for D.

[itex]C^{T}B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=C^{T}[/itex]

Homework Equations



[itex]C^{T}B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=C^{T}[/itex]

The Attempt at a Solution



I must have missed something in the reading of this section. All I can think of is

[itex]B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=I[/itex]

but I don't know where to go from there or if it is even the right way to start.
 
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Left-multiply the third equation with B.
 
stumpoman said:

Homework Statement


Assuming that all matrices, A, B, C, and D, are n x n and invertible, solve for D.

[itex]C^{T}B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=C^{T}[/itex]
Just "undo" every thing that is done to D, one step at a time. For example if you multiply both sides, on the left, by [itex](C^T)^{-1}[/itex] you get [itex]B^{-1}A^{-2}BAC^{-1}DA^{-2}B^TC^{-2}= (C^T)^{-1}C^T= I[/itex]
Then multiply on the left by [itex]B[/itex], then on the right by [itex]C^2[/itex], or do both together to get [itex]A^{=2}BAC^{-1}DA^{-2}B^T= BC^2[/itex].
Continue to "unpeel" D.

Homework Equations



[itex]C^{T}B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=C^{T}[/itex]

The Attempt at a Solution



I must have missed something in the reading of this section. All I can think of is

[itex]B^{-1}A^{2}BAC^{-1}DA^{-2}B^{T}C^{-2}=I[/itex]

but I don't know where to go from there or if it is even the right way to start.
Yes, that was the first step as I showed. Continue in the same way.
 

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