An rectangular object(mass m) sliding on a horizontal plane (surface is frictionless), with a speed V, object height H.
then hits a rectangular obstacle with height h. V is large enough to cause tripping
what is the relation between linear momentum / angular momentum / conservation of momentum
The Attempt at a Solution
is this what's happening; the object has a momentum of P=mV.
then an impulse I=t*F is applied to the object by the obstacle.
This impulse reduces the linear momentum to P'=m*V-F*x
---This m*V-Fx gives the angular momentum(with respect to the point of contact) causing the rotation?---
I am not sure if my thinking is correct, especially my last statement.
An alternative is; taking initial mV as an angular momentum with changing radius wrt the contact point??? ie not mentioning linear momentum at all?
Thanks in advance.