Linear/angular Momentum / tripping / conservation

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Homework Help Overview

The discussion revolves around a rectangular object sliding on a frictionless horizontal plane that collides with a rectangular obstacle, leading to questions about linear and angular momentum, as well as the conditions for tripping. Participants explore the relationship between linear momentum, angular momentum, and the conservation of momentum in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the momentum of the object before and after the collision, considering the effects of an impulse from the obstacle. There are questions about the relevance of linear versus angular momentum and whether to incorporate forces or time into the analysis. Some participants suggest deriving a formula to understand the speed threshold for tripping.

Discussion Status

The discussion is active, with participants providing insights into the mechanics of the problem. There is a focus on identifying the appropriate conservation laws to apply, particularly regarding angular momentum. Some guidance has been offered about selecting a reference point to simplify the analysis of the impulse.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is uncertainty regarding the choice between momentum and energy equations, as well as the implications of the unknown impulse at the point of impact.

timarli
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Homework Statement



An rectangular object(mass m) sliding on a horizontal plane (surface is frictionless), with a speed V, object height H.
then hits a rectangular obstacle with height h. V is large enough to cause tripping

Homework Equations



what is the relation between linear momentum / angular momentum / conservation of momentum


The Attempt at a Solution



is this what's happening; the object has a momentum of P=mV.
then an impulse I=t*F is applied to the object by the obstacle.
This impulse reduces the linear momentum to P'=m*V-F*x
---This m*V-Fx gives the angular momentum(with respect to the point of contact) causing the rotation?---


I am not sure if my thinking is correct, especially my last statement.

An alternative is; taking initial mV as an angular momentum with changing radius wrt the contact point? ie not mentioning linear momentum at all?


Thanks in advance.
 
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timarli said:
is this what's happening; the object has a momentum of P=mV.
then an impulse I=t*F is applied to the object by the obstacle.
It won't be useful to introduce F or t. Just leave it as I.
This impulse reduces the linear momentum to P'=m*V-F*x
x?
---This m*V-Fx gives the angular momentum(with respect to the point of contact) causing the rotation?---
I provides the angular momentum.
To solve the problem, you need to use a fact concerning subsequent motion of the block.. like, some point that is stationary immediately after impact.
 
haruspex said:
It won't be useful to introduce F or t. Just leave it as I.

x?

I provides the angular momentum.
To solve the problem, you need to use a fact concerning subsequent motion of the block.. like, some point that is stationary immediately after impact.

Thanks a lot haruspex.

x was wrong, well spotted. It should be 't'.

what I am trying to do is derive a formula to show the affect of speed on the tripping.

Assuming the object is a car and the obstacle is a concrete block; I would like to find out what's the speed above which the car will trip. So the top of concrete can be the reference point.

I know the mass, I know the object height and center of gravity and obstacle height. I am still struggling to figure out writing the equation. Not sure if I need to use momentum equations or energy equations.
 
timarli said:
Not sure if I need to use momentum equations or energy equations.
You need to pick the one that's conserved. There is an unknown impulse at the point of impact, and it clearly does not conserve work. The best, then, is to take angular momentum, picking a reference point that makes the unknown impulse have zero moment.
 
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