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Linear Combination - Are these solutions wrong?

  1. Jan 27, 2015 #1
    j8k46SV.jpg

    I, II represent rows 1 and 2, respectively.

    I am not agreeing with these solutions at step 3 of 5, where they multiply row 2 by 1/(b-a). Correct me if I'm wrong, but we do not know if b-a=0, so I do not think we can divide row II by (b-a) because of the potential of dividing by 0?

    What do you guys think?
     
  2. jcsd
  3. Jan 27, 2015 #2

    Mark44

    Staff: Mentor

    I agree with you. From the given information, we can't say that b - a ≠ 0.
     
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