Linear Combination - Are these solutions wrong?

  • Thread starter pyroknife
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  • #1
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I, II represent rows 1 and 2, respectively.

I am not agreeing with these solutions at step 3 of 5, where they multiply row 2 by 1/(b-a). Correct me if I'm wrong, but we do not know if b-a=0, so I do not think we can divide row II by (b-a) because of the potential of dividing by 0?

What do you guys think?
 

Answers and Replies

  • #2
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j8k46SV.jpg


I, II represent rows 1 and 2, respectively.

I am not agreeing with these solutions at step 3 of 5, where they multiply row 2 by 1/(b-a). Correct me if I'm wrong, but we do not know if b-a=0, so I do not think we can divide row II by (b-a) because of the potential of dividing by 0?

What do you guys think?
I agree with you. From the given information, we can't say that b - a ≠ 0.
 

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