Finding Constants for Linear Dependence in 3D Vectors

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The discussion centers on determining constants for proving linear dependence among three 3D vectors. The vectors A, B, and C are shown to be linearly dependent through the equation 2A - 3B + C = 0. A participant initially considers Gaussian elimination but struggles with the setup of the equations. After clarification, the correct system of equations is identified, leading to the realization of previous errors in formulation. The conversation highlights the importance of correctly setting up equations for linear algebra problems and the utility of Gaussian elimination in solving them.
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Going through a mathematical physics book in the section about vector spaces, in the section showing how to prove vectors are linearly dependent their example is:

Two vectors in 3-d space:

A = i + 2j -1.5k
B = i + j - 2k
C = i - j - 3k

are linearly dependent as we can write down

2A - 3B + C = 0

I understand the concept of linear dependence, and why the answer makes sense (non-zero constants exist) but my question is how they determined the constants needed to show the vectors are dependent. My first thought was Gaussian elimination but I don't think that's correct.

Any help would be appreciated.
 
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You're right in suspecting Gaussian elimination as one way to find them, but can you figure out why?
Start with xA + yB + zC = 0 where x, y, and z are the unknown constants and try and solve for them. You should find a system of three equations in three unknowns.

Also, welcome to PF.
 
Thank you. So I get something like this (eliminating x):

x + 2y - 1.5z = 0
-y - .5z = 0
-3y - 1.5z = 0

I can't remember how to solve a set of equations like this where they are all set to zero.
I thought the process was once a variable is eliminated, to solve for say cy = z
then set z=t and try to plug back to find x. When I do this, I do not come up with 2, -3, 1 or any multiples of them.
 
Your starting equations should have been:
x + y + z = 0
2x + y - z = 0
-1.5x - 2y - 3z = 0

From this, put it into a matrix and use Gaussian elimination. If you don't know what I'm talking about, you should start from the beginning of linear alg.
Here's some notes for a introduction to linear algebra class for reference.
http://tutorial.math.lamar.edu/Classes/LinAlg/LinAlg.aspx
 
Vid said:
Your starting equations should have been:
x + y + z = 0
2x + y - z = 0
-1.5x - 2y - 3z = 0

I know how to use Gaussian, but when I originally worked it out I had put the starting equations in wrong. That's why in the OP I thought I was wrong for using that method. Now that you posted the correct starting equations, I see my error. Thanks a lot, I sure wasted a lot of time getting hung up on a simple problem haha.
 
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