1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Linear Equations - Cramer's Rule

  1. Feb 19, 2012 #1
    1. The problem statement, all variables and given/known data

    Does the following set of linear equations have a unique solution?

    (excluding any trivial solutions when x=y=z=0)

    Do not attempt to formally solve the equations.

    x+2y-4z=8
    4x-6y+12z=19
    -6x+3y-6z=-20



    2. Relevant equations



    3. The attempt at a solution

    My immediate thought would be to solve the equations using Cramers Rule. However, it states not to formally solve the equations. So I assume I'm not allowed to do this.

    So what does the question mean me to do?
     
  2. jcsd
  3. Feb 19, 2012 #2

    Mark44

    Staff: Mentor

    Rewrite the system of three equations as a matrix equation in the form Ax = b. Here x represents the vector <x, y, z>T, and b represents the constant vector <8, 19, -20>T. What conditions on matrix A guarantee a unique solution to the equation?
     
  4. Feb 19, 2012 #3
    By ^T do you mean transpose?

    Just wanted to check before attempting to try and solve this.
     
  5. Feb 19, 2012 #4
    If I take the matrix;

    1, 2, -4
    4, -6, 12
    -6, 3, -6

    The determinant = 0

    Therefore it is not invertible.

    Therefore this implies it has no unique solution.

    Is this correct?
     
  6. Feb 19, 2012 #5

    Mark44

    Staff: Mentor

    Yes.
    A better way is to say that it has no solution. A system of equations can have
    1) a unique solution
    2) multiple solutions (an infinite number of them)
    3) no solutions

    If you say "no unique solution" this might be interpreted as multiple solutions.
     
  7. Feb 19, 2012 #6
    Okay. Thank you.
     
  8. Feb 19, 2012 #7

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    But isn't "no unique solution" what he wants to say? The question, after all, was "Does the following set of linear equations have a unique solution?" The fact that the determinant of this 3 by 3 set of equations is 0 means it maps R3 into a proper subspace of R3. If the right hand side doesn't happen to be in that subspace, there is no solution but if it does, an entire subspace will be mapped to it.
     
  9. Feb 19, 2012 #8

    Mark44

    Staff: Mentor

    For this particular problem, there is no solution. I am distinguishing between "no unique solution" and "no solution" as the former term might be interpreted by some to mean that there are multiple solutions (i.e., not a unique solution). That was the distinction I was trying to make.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Linear Equations - Cramer's Rule
  1. Linear Equations (Replies: 8)

  2. Linear Equations (Replies: 2)

  3. Linear Equations (Replies: 2)

  4. Linear equation (Replies: 3)

Loading...