- #1
nufc365
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Hi, I am doing self study and have hit a snag in the road. Can someone please clarfiy this for me. I am reading K.A. Stroud's Engineering Mathematics which so far has been great.Consider the equation [itex]\frac{dy}{dx}[/itex] + 5y = e2x
In this case, we begin multiplying both sides by e5x. This gives
e5x[itex]\frac{dy}{dx}[/itex] + y5e5x = e2x.e5x = e7x
We now find that the left-hand-side is the derivative of y.e5x.
[itex]\frac{d}{dx}[/itex](y.e5x) = e7x____________________
Can someone please clarify how the left hand side is the derivative of y.e5x.
I get that y5e5x is the derivative of y.e5x, but what about the first part of the left-hand-side. What happens to the e5x[itex]\frac{dy}{dx}[/itex]
In this case, we begin multiplying both sides by e5x. This gives
e5x[itex]\frac{dy}{dx}[/itex] + y5e5x = e2x.e5x = e7x
We now find that the left-hand-side is the derivative of y.e5x.
[itex]\frac{d}{dx}[/itex](y.e5x) = e7x____________________
Can someone please clarify how the left hand side is the derivative of y.e5x.
I get that y5e5x is the derivative of y.e5x, but what about the first part of the left-hand-side. What happens to the e5x[itex]\frac{dy}{dx}[/itex]