Linear expansion of steel question

Click For Summary
SUMMARY

The discussion centers on solving a linear expansion problem for steel using the equation ΔL = αLΔT, where α is the linear expansion coefficient for steel at 12 x 10-6 K-1. The user faced challenges due to the absence of the initial length of the steel in the problem statement. A solution was proposed by assuming a cube with an edge length of 1 meter, allowing for the calculation of the new length and subsequent change in density using the relationship density = mass/volume.

PREREQUISITES
  • Understanding of linear expansion equations
  • Familiarity with the coefficient of linear expansion (α)
  • Basic knowledge of density calculations
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Explore the concept of thermal expansion in materials
  • Study the relationship between density, mass, and volume in detail
  • Learn about the properties of steel and its thermal characteristics
  • Investigate dimensional analysis to ensure equation validity
USEFUL FOR

Students studying physics or engineering, particularly those focusing on material properties and thermal dynamics, will benefit from this discussion.

ilyas415
Messages
5
Reaction score
0

Homework Statement



The question i need help on is question 6 part (c). I think I need to use the equation:

2. Equations used:
\DeltaL = \alphaL\DeltaT

Linear expansion of steel: 12x10 K^-1 (\alpha)
Density of steel: 7800

3. My attempted solution:
I tried substituting in the values into the equation but the question did not mention anything about the length of the steel so now i am stuck for a solution. I tried using proportionality with density=mass/volume so density is proportional to 1/L. However I am not sure this if this is the correct way.

Thanks for your help in advance.
 

Attachments

Last edited:
Physics news on Phys.org
That equation doesn't make dimensional sense; it has meters on the left but is dimensionless on the right. After that issue's fixed, you could try assuming a side length of 1 m, or 2 m. Does it make a difference?
 
ah, I've got it, assume it is a cube with edge length 1m, then I've got to substitute 1m into the equation to find the new length, then i use density = mass/volume, then i get the change in density
 

Similar threads

Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K