Linear Mappings: Solving for Dimension of Nullspace

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SUMMARY

The discussion centers on solving for the dimension of the nullspace in linear mappings, specifically through transformations A: Rn → R and B: Rn → R2. The participant successfully determined the dimension of the nullspace for transformation A and sought guidance for part B, which involves analyzing a different linear map B that incorporates vectors \(\vec{a}\) and \(\vec{b}\). The conclusion reached is that if \(\vec{a}\) and \(\vec{b}\) are linearly independent, then the dimension of the intersection of the spaces S and T is n - 2, leading to a straightforward generalization for part C.

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Homework Statement



http://img526.imageshack.us/img526/743/93134049.png


Homework Equations


Just the standard linear mapping properties and theorums.


The Attempt at a Solution



I have already solved part A by considering the transformation A: Rn -> R | A(x) = a.x where x is a vector in Rn, and finding the dimension of the nullspace.

I am stuck on where to begin the proof for part b, once I have b I don't think I will have a problem generalizing it for part c.
 
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Your solution to part (a) already contains the essence of a solution to part (b); just think about the dimension of the null space of a different linear map B, one that uses the existence of \vec{a} and \vec{b} both.

(If you need a further hint: given that you are supposed to find that \dim(S \cap T) = n - 2 in case \vec{a} and \vec{b} are linearly independent, what do you think the dimension of the range space of B ought to be?)
 
ah, thank you, very good. I have a transformation B: Rn -> R2 that works nicely, and the generalization follows quite easily.
 

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